How Does Changing the Medium Affect the Frequencies of Tubes in Sound Physics?

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SUMMARY

The discussion focuses on the relationship between the lengths of closed and open tubes and their fundamental frequencies in sound physics. A closed tube measuring 50 cm has a corresponding open tube length of 100 cm, yielding a frequency of 172.5 Hz when calculated using the speed of sound in air (34,500 cm/s). The participants inquire about the effects of placing these tubes in a gas with a higher speed of sound, specifically whether their fundamental frequencies remain equal and whether they increase or decrease.

PREREQUISITES
  • Understanding of fundamental frequency calculations for sound waves
  • Knowledge of the speed of sound in different media
  • Familiarity with the equations for open and closed tubes: v/2L and v/4L
  • Basic principles of sound wave propagation
NEXT STEPS
  • Research the effects of different gases on the speed of sound
  • Explore the concept of harmonics in closed and open tubes
  • Learn about the physics of sound wave interference
  • Investigate the relationship between tube length and frequency in various media
USEFUL FOR

Students studying sound physics, educators teaching acoustics, and anyone interested in the principles of wave behavior in different mediums.

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Homework Statement


A closed tube filled with air is 50cm long.
a. what is the length of an open tube that has the same fundamental frequency? 100cm (34,500cm/s^2 / 2(100cm)
b. what is the frequency? 172.5 (34,500cm/s^2 / 4 (50cm)

I got these two but, need help on this:
c. These two tubes are placed in a gas with a speed of sound grteater than the sound in air. Do the frequencies of their fundamentals remain equal to each other?
d. Do they increase or decrease?

Homework Equations



v/2L (fundamental frequency of the first harmonic, open tube)
v/4L (fundamental frequency of the first harmonic, closed tube)

L = length of tube

The Attempt at a Solution

By CLOSED tube in all these problems - it means closed on ONE SIDE only.
 
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longestline1 said:

Homework Statement


A closed tube filled with air is 50cm long.
a. what is the length of an open tube that has the same fundamental frequency? 100cm (34,500cm/s^2 / 2(100cm)
b. what is the frequency? 172.5 (34,500cm/s^2 / 4 (50cm)

I got these two but, need help on this:
c. These two tubes are placed in a gas with a speed of sound grteater than the sound in air. Do the frequencies of their fundamentals remain equal to each other?
d. Do they increase or decrease?

Homework Equations



v/2L (fundamental frequency of the first harmonic, open tube)
v/4L (fundamental frequency of the first harmonic, closed tube)

L = length of tube



The Attempt at a Solution




By CLOSED tube in all these problems - it means closed on ONE SIDE only.

So, tell us. What is 'v' in the equations you have written?
 

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