How Does Charge Distribute Between Two Concentric Shells Connected by a Wire?

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In the discussion about charge distribution between two concentric conductive shells connected by a wire, it is established that the voltage at both ends of the wire must be equal. The initial assumption is that all charge would reside on the outer shell, resulting in a distribution of 0 nc on the inner shell and 100 nc on the outer shell. However, the correct approach involves using the formula Q1/Q2 = R1/R2, which accounts for the ratio of the radii of the shells. The conclusion emphasizes that with no potential difference, there is no electric field, and thus no charge within the Gaussian volume just inside the outer shell. The final charge distribution is confirmed to be correct based on this analysis.
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Homework Statement


The problem states:
2 concentric shells made out of conductive materials as in the diagram. R2/ R1 = 6. If the shells were charged with a total charge of 100 nc the connected with a wire, Then the final charge on both shells would be?
1) 33.3, 66.7 2) 30, 70 3) 20, 80 4) 50,50 5) 14.3,85.7

Homework Equations


Voltage at both end points of the wire should be the same

The Attempt at a Solution


Shouldn't all the charge go to the outer shell? So it will be 0, 100

The solution provided used this formula:
Q1/ Q2 = R1/R2
https://prnt.sc/jmp453

Where we only used this formula for the case of two really far conducting shells connected with a wire.

Exam tomorrow, Thank you in advance.
 
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While I’m sure someone will respond, my suggestion is to seek out a fellow student and see if you both can work this out since you’re concerned about your exam and we may not answer in time.
 
Conductivity said:
Shouldn't all the charge go to the outer shell?
It should. No potential difference between the two shells means no electric field. No field means no charge: a Gaussian volume, spherical, just inside the outer shell should not contain any charge.

Your answer is correct.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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