How Does Charge Distribution Affect Electric Fields in Nested Spheres?

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The discussion centers on the electric field generated by a solid sphere of radius 3.00 cm with a net charge of +4.33 fC, which is concentric with a spherical conducting shell that has a net charge of -4.33 fC. The confusion arises regarding the electric field at a distance of 1.50 cm (a/2) from the center of the sphere, where it is established that the electric field is not zero despite the presence of a conducting shell. This is clarified by noting that the solid sphere is not a conductor, allowing for an electric field to exist within its volume.

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A solid sphere of radius a = 3.00 cm is concentric with a spherical conducting shell of inner radius b = 2.00a and outer radius c = 2.40a. The sphere has a net uniform charge q1 = +4.33 fC; the shell has a net charge q2 = –q1.

What is the magnitude of the electric field at a distance r = a/2 from the center of the sphere?

___

Well, I thought the answer was 0 because as I know, the electric field inside a conductor is zero, and the sphere is a conductor. So anywhere in the sphere will have zero charge, since all the charge moves to the surface of the sphere. But, the answer is not zero. Why is this? I'm just so entirely confused with when E is zero and when it is not.

Thanks.
 
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It was not said that the solid sphere was a conductor.

ehild
 

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