How Does Compton Scattering Affect Photon Wavelength at 90 Degrees?

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Homework Help Overview

The discussion revolves around Compton scattering and its effect on the wavelength of photons, specifically at an angle of 90 degrees. The original poster presents a problem involving the percentage change in wavelength, ΔΛ/Λ, and seeks to determine the wavelength of the photons after scattering.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the change in wavelength and the original wavelength, referencing the definition of Δλ. There is uncertainty about how to apply the given percentage change to the problem.

Discussion Status

Participants are exploring the definitions related to wavelength change and attempting to clarify how to use the provided percentage in the context of the problem. There is an acknowledgment of the formula for Δλ, but no consensus on its application has been reached.

Contextual Notes

There is a repeated emphasis on the percentage change in wavelength, ΔΛ/Λ = 1.5%, which appears to be a key aspect of the problem that participants are trying to interpret correctly.

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Homework Statement


The length of the photon waves which are under Compton scattering ( compton scattering is applied on them) is measured in the angle =90 degree.If ΔΛ/Λ is 1.5 %,what is the length of the waves of the falling photons?


Homework Equations



a5538f90db08abca4bab0597af48b05c.png


The Attempt at a Solution



The only problem here is ΔΛ/Λ = 1.5 %, I don't know how to relate that to the above formula..
 
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Elaia06 said:

Homework Statement


The length of the photon waves which are under Compton scattering ( compton scattering is applied on them) is measured in the angle =90 degree.If ΔΛ/Λ is 1.5 %,what is the length of the waves of the falling photons?


Homework Equations



a5538f90db08abca4bab0597af48b05c.png


The Attempt at a Solution



The only problem here is ΔΛ/Λ = 1.5 %, I don't know how to relate that to the above formula..

By definition, Δλ = (λ' - λ)/λ.
 
rude man said:
By definition, Δλ = (λ' - λ)/λ.
I think that should be Δλ = (λ' - λ) or Δλ/λ = (λ' - λ)/λ.
 
mfb said:
I think that should be Δλ = (λ' - λ) or Δλ/λ = (λ' - λ)/λ.

Right. Sorry.
 

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