How Does Constant Force Affect Kinetic Energy Over Time?

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SUMMARY

The discussion focuses on the effect of a constant force on the kinetic energy of a bead with a mass of 1.8x10^-2 kg moving along a wire. Initially, the bead has a speed of 12 m/s, resulting in a kinetic energy (KE) of 1.296 J at time t=0. The bead comes to a stop at t=3.0 seconds due to the constant force acting on it. The key question raised is the calculation of the bead's velocity and kinetic energy at t=10 seconds, following the principles of kinematics and energy conservation.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with the kinetic energy formula K=(0.5)mv^2
  • Knowledge of kinematic equations, specifically vf^2=vi^2+2ad
  • Basic grasp of forces and their impact on motion
NEXT STEPS
  • Calculate the final velocity of the bead at t=10 seconds using kinematic equations.
  • Explore the relationship between force, mass, and acceleration in detail.
  • Investigate the concept of work-energy principle in physics.
  • Review examples of constant force scenarios in motion problems.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding the dynamics of motion under constant force conditions.

foxcub156
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Homework Statement


A bead with mass (1.8x10^-2)kg is moving along a wire in the positive direction of an x axis. Beginning at time=0, when the bead passes through x=0 with speed 12m/s, a constant force acts on the bead, the picture indicates the bead's position at these four times: t0=0 sec., t1=1.0 sec., t2=2.0 sec., t3=3.0 sec., The bead momentarily stops at t=3.0 sec. What's the kinetic energy of the bead as t=10 sec?

Homework Equations


K=(.5)mv^2

vf^2=vi^2+2ad

The Attempt at a Solution



Is the answer K=1.296? I really think it's wrong.
 
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That seems to be the initial KE, If under constant force it took 3 seconds to stop, what will the velocity be after 10s?
 

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