How Does Coulomb's Law Apply When Socks Repel in a Dryer?

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SUMMARY

The discussion focuses on applying Coulomb's Law to determine the force between two socks with equal charges when separated by different distances. Initially, the force is 0.002 N at a distance of 1 cm. By calculating the charge using the formula F = k(q1)(q2) / r², where k = 8.9 x 10^9 N m²/C², the charge is found to be approximately 4.74 x 10^-9 C. When the socks are separated to 5 cm, the force can be recalculated using the same formula.

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Homework Statement



You remove two socks from a hot dryer and find that they repel with force of 0.002 N when they’re 1 cm apart. If they have equal charges, and you separate the socks until they’re 5 cm apart, what force will each sock exert on the other? Round the answer to 3 significant digits.

Homework Equations



F=8.9*10^9(q1)(q2) / r^2

The Attempt at a Solution



Ive been working on this for over an hour and am frieking out! First I try to solve for the two charges, using .1 (1cm-converted to meter). I know that once I get this, I can use it to change .1 to .5 and solve for F. Problem is I have been having trouble solving for Q! which leaves me stuck in the begining.

Please please help, I've got a midterm in the morning.:confused:
 
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F=kq1q2/r^2

at .01m, F = .002
Solve for q^2, since q1 = q2
q^2= (0.002)(.01^2) / (8.9e+9)
= 2.25e-17 C
so q1 or q2 equals the square root of q^2:
(2.25e-17)^0.5 = 4.74e-9 C

Then, use these values to solve if r = .05 (just plug them back into the equation)

I hope this helped
 

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