How does dimensional analysis account for additive variables in equations?

Mr Davis 97
Messages
1,461
Reaction score
44
Under the standard form of dimensional analysis, I know that we relate a dependent variable to a function of the independent variable(s). However, what if there is some additive variable needed in the equation? How does this method, which expresses all of the independent variables as a product of the variables (with the exponents being any real number) times a constant, account for the needed addition of operations such as subtraction and addition? How can we derive correct equations if there is a missing sum or difference needed in the formula?
 
Physics news on Phys.org
If you can construct a specific unit with multiple independent expressions, then dimensional analysis for this unit does not work.
A trivial example is a setup where you have two velocities, or two masses or something similar. There is no way to figure out which velocity/mass/... to use just by dimensional analysis.
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
679
  • · Replies 5 ·
Replies
5
Views
3K
Replies
9
Views
2K
Replies
67
Views
9K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K