How Does Earth's Magnetic Field Flux Change with Loop Orientation?

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Homework Help Overview

The discussion revolves around calculating the magnetic flux of Earth's magnetic field through a square loop, specifically addressing two scenarios: when the magnetic field is perpendicular to the loop and when it is at a 20° angle to the normal of the loop. The magnetic field's magnitude is given as 5.00 x 10^-5 T, and the area of the loop is specified as 40.0 cm².

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the magnetic flux using the formula flux = BA cos theta but encounters issues with unit conversion from cm² to m². Some participants question the understanding of the conversion process and its implications on the calculations.

Discussion Status

Participants are actively discussing the correct conversion of area units and its impact on the calculations. There is a focus on clarifying the proportionality between cm² and m², indicating a productive exploration of the underlying assumptions.

Contextual Notes

The original poster's calculations are based on an incorrect area conversion, which is a key point of confusion in the discussion. The problem statement does not provide additional constraints or information beyond the given parameters.

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Magnetic flux!

Homework Statement


Find the flux of Earth's magnetic field of magnitude 5.00 10-5 T through a square loop of area 40.0 cm2 for the following:
(a) when the field is perpendicular to the plane of the loop



(b) when the field makes a 20.0° angle with the normal to the plane of the loop


Homework Equations



flux = BA cos theta
where A is the area and B is the magnetic field



The Attempt at a Solution


on the first one i just multiplied 5e-5 by .4 and i got 2.0e-5... and it was wrong and i have NO idea why

the second one i just used the answer i got previously (obviously wrong) and multiplied it by cos of 20... red x
HELP!
 
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You have to convert cm^2 to m^2 in the correct way
 


borgwal said:
You have to convert cm^2 to m^2 in the correct way

the correct way? its not directly proportional?
 


It's directly proportional, but not with the proportionality constant you think!

You seem to think that 40 cm^2 equals 0.4 m^2. That's not true!
 

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