Magnetic Flux Through a Square Loop

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Homework Help Overview

The problem involves calculating the magnetic flux through a square loop of wire, given its dimensions and the angle it makes with a uniform magnetic field. The subject area pertains to electromagnetism, specifically magnetic flux and its calculation using the formula Φ = BAcosθ.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the interpretation of the angle θ in the magnetic flux formula, questioning whether it corresponds to the angle between the loop's plane and the magnetic field or the angle between the normal to the loop and the magnetic field. There is an attempt to clarify the relationship between these angles and their impact on the magnetic flux calculation.

Discussion Status

The discussion is actively exploring the correct interpretation of the angle in the magnetic flux formula. Some participants have provided clarifications regarding the angle's definition, while others are questioning assumptions about the problem setup. There is no explicit consensus yet, but productive dialogue is ongoing.

Contextual Notes

Participants are considering the implications of the angle given in the problem statement and its relevance to the calculation of magnetic flux. There is an acknowledgment of potential confusion regarding the angles involved in the formula.

ilovejava
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Homework Statement


A loop of wire in the form of a square 1.50 m on each side, its plane makes an angle of 40.0° with a uniform magnetic field of 0.95 T. What is the magnetic flux through the loop?

Homework Equations


Φ = BAcosθ
A = s^2

The Attempt at a Solution


I found the area of the square using A = s^2 which returns 2.25m. Then I just plugged in the values provided in the question making sure to use 40°. I got Φ = 1.64Wb but the answer is 1.37Wb
 
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In the formula Φ = BAcosθ, can you describe in words the meaning of the angle θ? What particular angle does it represent?

The angle of 40.0° given in the statement of the problem might not be the angle represented by θ in the formula.
 
TSny said:
In the formula Φ = BAcosθ, can you describe in words the meaning of the angle θ? What particular angle does it represent?

The angle of 40.0° given in the statement of the problem might not be the angle represented by θ in the formula.
The angle in the formula is the angle the loop makes with respect to the magnetic field. If the angle was 90 the the magnetic flux would be zero because no magnetic field lines would pass through the loop.
 
ilovejava said:
The angle in the formula is the angle the loop makes with respect to the magnetic field. If the angle was 90 the the magnetic flux would be zero because no magnetic field lines would pass through the loop.
θ is not the angle that the plane of the loop makes to the magnetic field.

The picture below shows the case where the plane of the loop makes a 90o angle to the B field.
upload_2017-3-4_17-30-52.png

Would you say that the flux through the loop is zero here?
 
TSny said:
θ is not the angle that the plane of the loop makes to the magnetic field.

The picture below shows the case where the plane of the loop makes a 90o angle to the B field.
View attachment 114102
Would you say that the flux through the loop is zero here?
No the flux through the loop is not zero. I guess it's the angle made between the normal of the loop and the magnetic field?
 
ilovejava said:
No the flux through the loop is not zero. I guess it's the angle made between the normal of the loop and the magnetic field?
Yes, θ in the formula is the angle between the normal of the loop and the magnetic field.
 

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