How Does Energy Transfer Work in Pendulums?

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SUMMARY

The discussion centers on the principles of energy transfer in pendulums, specifically the relationship between potential and kinetic energy. It is established that the energy required to raise a pendulum bob to its maximum height (calculated as mass x gravity x height) is equal to the kinetic energy at the equilibrium position during its oscillation, assuming negligible friction. The conversation emphasizes that gravity acts as a store of energy rather than a source, clarifying misconceptions about gravity-powered machines.

PREREQUISITES
  • Understanding of gravitational potential energy (mgh)
  • Basic knowledge of kinetic energy and energy conservation principles
  • Familiarity with pendulum mechanics and oscillatory motion
  • Awareness of friction's impact on energy transfer in physical systems
NEXT STEPS
  • Study the principles of energy conservation in mechanical systems
  • Explore the dynamics of simple harmonic motion in pendulums
  • Investigate the effects of friction on energy loss in oscillatory systems
  • Learn about gravitational potential energy in various contexts, such as hydroelectric systems
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Physics students, educators, and anyone interested in understanding the mechanics of pendulums and energy transfer principles in oscillatory systems.

BMZoobie
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Hi everyone, I'm new to this sight/forum so I apologies in advance if I've got the wrong platform or have made any other faux par.

This is probably very elementary to most on this forum; can someone please tell me and hopefully explain a few things around transfer of energy in pendulums. Here is what I am pondering...

Is the energy required to raise a pendulum bob to its point of maximum potential energy more, less or equal to the energy then seen in the movement of the bob back and forth through the resulting oscillations? - I realize that the exact measurements of this depends on the design of the pendulum and assumes a relatively low level of friction but I'm more or less just referring to a string with a spherical weight suspended one one end and fixed to a fulcrum point at the other.

From my limited understanding of this matter I would think that the sum of the energy (mass X gravity X height) needed to send the bob flying past its point of equilibrium a number of times is collectively greater than the initial energy requirement to raise the bob from equilibrium to its point of maximum potential energy, this extra energy being drawn from Earth's gravity.

Can someone please confirm if my understanding is correct of if not explain why and what is actually happening?

Thanks,

Abz
 
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BMZoobie said:
From my limited understanding of this matter I would think that the sum of the energy (mass X gravity X height) needed to send the bob flying past its point of equilibrium a number of times is collectively greater than the initial energy requirement to raise the bob from equilibrium to its point of maximum potential energy, this extra energy being drawn from Earth's gravity.
The energy needed to raise the mass from the lowest point to a height h equals mgh. At the highest point, all the energy is gravitational potential. As it falls, that energy is transformed into kinetic energy. The total energy, ignoring friction and other losses, is conserved as the pendulum swings back and forth.
 
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BMZoobie said:
needed to send the bob flying past its point of equilibrium
Its kinetic energy at the equilibrium position will, ideally, be exactly the same as the potential energy at the greatest displacement. The term "flying" seems to imply that it would be more? It couldn't be, without a supply of extra energy.
No different ideas here than in @Doc Al 's post - just put a different way.
 
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Gravity can never be a "source" of energy. It's only ever a store of energy. A hydro electric dam stores energy but the source is the sun as it's the sun that provides the energy to raise the water/rain.

Anyone claiming they have made a gravity powered machine is mistaken.
 
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