How Does Exciting a Hydrogen Atom Affect Its Kinetic and Potential Energy?

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SUMMARY

Exciting a hydrogen atom from its ground state results in a decrease in kinetic energy (K.E) and an increase in potential energy (P.E). The discussion highlights that as the principal quantum number (n) increases, both K.E and P.E are inversely proportional to 1/n². The correct interpretation, as clarified in the discussion, is that while K.E decreases, P.E increases due to the negative sign in the potential energy expression, which indicates that a decrease in magnitude leads to an increase in potential energy.

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1. When a hydrogen atom is excited from the ground state;
a) K.E & P.E both increases
b)K.E & P.E both decreases
c) K.E increase and P.E decrease
d) K.E decrease & K.E increase.

ATTEMPT

K.E[tex]\propto[/tex]1/n2

P.E[tex]\propto[/tex]1/n2

so n increases both decreases. >>>>option b is right for me.


but the correct answer given in book is option d

wer I'm wrong
 
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the thing you foud for PE is its mag only
write the expression of PE of electron and proton
here you'll see a - sign
so if mag decrease ... due to - sign ... PE inc
 

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