How Does Flipping a Ring Affect Magnetic Flux and Induced EMF?

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Homework Help Overview

The discussion revolves around calculating magnetic flux and induced EMF related to a wedding ring in the context of Earth's magnetic field. The problem involves determining the flux through the ring when held in a horizontal plane, analyzing the change in flux when the ring is flipped, and applying Faraday's law to find the induced EMF during this process.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the calculation of magnetic flux using the dot product of magnetic field and area vectors. There are attempts to clarify the angle involved in the calculations and the implications of flipping the ring on the flux. Some participants express confusion about specific steps in the calculations for parts b and c.

Discussion Status

Several participants are actively engaging with the problem, offering hints and partial guidance. There is a recognition of the need for clarification on certain aspects, particularly regarding the calculations for the change in flux and the induced EMF. Multiple interpretations of the problem are being explored.

Contextual Notes

Participants note the complexity of the problem and the potential for misunderstanding due to the angle of the magnetic field relative to the ring. There is also mention of homework constraints, as some participants are working on the same assignment.

ghostbuster25
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The Earth’s magnetic field at a certain location in the UK has a magnitude of 48 μT and is directed at 66° below the horizontal.

a)Determine the magnitude of the flux of the Earth’s magnetic field through a
wedding ring of diameter 2.2 cm when the ring is held in a horizontal plane.

b)What is the magnitude of the flux change when the ring is flipped through 180° about a horizontal axis?

c)Use Faraday’s law to calculate the EMF induced in the ring when it is flipped
through 180° in 0.2 s, assuming the flux changes uniformly during this time.


can anyone help me please i am completely stuck and don't know where to start :(
 
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You would actually probably be better off posting this in introductory physics, but that's okay, let me give you a hand anyway.

a) Remember that the equation for flux is \int \int \mathbf{B}\cdot d\mathbf{a}=\int \int B cos(\phi) da

b) You should have an intuitive guess about this, but go ahead and work it out.

c) Remember that EMF is \frac{d \Phi}{dt}
 
Hi ghostbuster remember the B dot A cross product rule that helped me and the angle is below thw horizontal so work out the angle you need
 
Not all that astonishingly, I have the same homework as ghostbuster. it's getting pretty late now though, but here are my tenuous attempts at the three questions:

a)


Magnetic flux = B dot A; this is the dot product of the B vector and the area vector, A

B = 48 x10^-6 T at 34 degrees from the normal vector to the the area

The A vector has magnitude = the area, and is directed perpendicular to the surface.
Mag A = (2.2 x 10^-2 m)^2

Therefore
flux = (48 x 10^-6 T) (Pi) [(2.2 x 10^-2 m)^2] (cos 34)
= 2.75 x 10^-6 T m ^2

(b)

The A vector changes direction

Δ flux = B A cos (156) – BA cos (34)
= ( -0.9135 - 0.8290) x 10^-8
= 1.7425 x 10^-8 T m2

[c]

Using Faraday's law

EMF = -N
dt

= -1 -1.7425 x 10-8 T m2
0.2 s

= 8.7125 x 10^-8 V

I had some help from a guy, who's reasoning I can't quite follow now he's gone. Part (a) makes most sense to me, but am rather lost with b and c. any help, or hints would be very gratefully recieved
 

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