How Does Friction Affect the Movement of a Thrown Turkey?

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SUMMARY

The discussion focuses on calculating the work done by friction on a 10 kg frozen turkey thrown horizontally across a surface with a coefficient of kinetic friction of 0.10. The participant correctly determined the force of kinetic friction to be 9.81 N and calculated the work done by friction over a distance of 10 meters as 98.1 Joules. Additionally, the speed of the turkey was calculated using the work-energy principle, yielding a result of 4.43 m/s. The calculations and methodology presented were confirmed as accurate by other forum members.

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Homework Statement



Alright well the problem is that 10 kg frozen turkey is thrown and goes horizontally on a surface with a 0.10 coefficient of kinetic friction. It travels for 10 meters. What is the work the friction does to stop the object. And what is the speed the frozen turkey is thrown at?

Homework Equations



eq.

W=f * d



The Attempt at a Solution



I did the problem I don't know if it is right, I am hoping you guys will tell me if I did.

First I got the weight of the turkey.
10 kg * 9.81 m/s^2 = 98.1 N downward

Then 98.1N * Coefficient of .10 = 9.81 N kinetic friction.

Then plugged that into the work equation W=9.81 * 10 meters = so I got the work
of friction to be 98.1 Joules.

Then to find the speed I did

98.1 joules = 10*v^2/2 then got it to equal 4.43 m/s. did I do these steps right? If not can somebody help me? Thanks.
 
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Looks good to me.
 
Doc Al said:
Looks good to me.

Really? Nice. If so thank you. If anyone finds an error please let me know. thank you :)
 

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