How Does Friction Affect the Speed of a Bowling Ball When It Starts Rolling?

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SUMMARY

The discussion focuses on the physics of a bowling ball transitioning from sliding to rolling down an alley, specifically analyzing the impact of friction on its speed. It establishes that the final speed of the bowling ball when rolling without slipping is 5/7 of its initial speed, denoted as v(0). The participants explored various equations, including kinetic energy (KE = 1/2*m*v^2) and torque (T = Ia), to derive this relationship. The conversation also highlighted the complexities of calculating the work done by friction and the significance of the distance variable D in the energy equation.

PREREQUISITES
  • Understanding of Newton's laws of motion (F = ma)
  • Familiarity with rotational dynamics (T = Ia)
  • Knowledge of kinetic energy equations (KE = 1/2*m*v^2)
  • Basic concepts of friction and its role in motion
NEXT STEPS
  • Research the concept of rolling without slipping in physics.
  • Study the relationship between torque and work in rotational motion.
  • Explore the derivation of energy conservation equations in dynamic systems.
  • Investigate the role of friction in different types of motion, particularly in sports physics.
USEFUL FOR

Physics students, educators, and anyone interested in the mechanics of motion, particularly in sports dynamics and the effects of friction on rolling objects.

Tamishu
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Homework Statement


One version: A bowling ball is thrown down the alley with speed v(0). Initially, it slides without rolling, but due to friction, it begins to roll. Show that it's speed when it rolls without sliding is 5/7*v(0) .
Another version: Given a bowling ball thrown down the lane with speed v(0) , find the speed v(f) in terms of v(0) at which the ball rolls without slipping.

Homework Equations


KE = 1/2*m*v^2
F = ma
v(f)^2 = v(0)^2 + 2ax
T = Ia
etc..

The Attempt at a Solution


My second idea was that the torque of the ball must equal the work due to friction. Following this line worked out, and I got that the final speed is 5/7 of the initial speed. Cool beans.
My first idea was to use conservation of energy. So...

1/2 * m * v(0)^2 = 1/2 *m * v(f)^2 + 1/2 * I * omega(f)^2 + F(fr) * D

Except... what is D? According to various methods I tried, it's NOT R*theta, or the x in the third equation, or even R*theta - x. I say it's not because I didn't get 5/7 for the answer. (I would admit to doing math wrong, except I sat down with my professor and watched him do it and get the same wrong answers that I did. So, either we both suck at math, or the answers were "right".)
Knowing what v-final is *supposed* to be, I went back and substituted it into my energy equation. I also substituted in F(fr)= ma = m * ((v(f)^2 - v(0)^2) / 2d )
I ultimately got D being 7/12 * d, d = distance the ball is translated.
(I assume this value will work if I plug it into my energy equation and try solving for v(f), but I did NOT double check.)

So, if my value for D is correct... what does it mean? It seems like a rather random number.
Or even if my value for D isn't correct... what am I supposed to use? And how am I supposed to find it?
 
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First, semantics: "torque" can never equal "work".

Second, the work done by friction is NOT equal to F*D, or even \int F(x) dx. The reason is that the point at which the frictional force acts (the bottom of the bowling ball) is moving at a different velocity than the center-of-mass of the ball. The work friction does per unit time is \vec{F}\cdot\vec{v} where \vec{v} is the velocity of the bottom of the ball. For instance, when the ball is rolling without slipping, friction does zero work (even though the frictional force is not zero)!
 

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