How Does Gauss's Law Apply to Nonuniform Spherical Charge Distributions?

  • Thread starter Thread starter kbwelch17
  • Start date Start date
  • Tags Tags
    Calculus Charge
Click For Summary
SUMMARY

This discussion focuses on applying Gauss's Law to a nonuniform spherical charge distribution defined by the charge density ρ(r) = ρ0(1-r/R) for r≤R, where ρ0 = 3Q/∏R^3. Participants clarify that to find the total charge Q, one must integrate the charge density over the volume of the sphere, rather than using Gauss's Law directly. The electric field for r≥R behaves like that of a point charge Q at the origin, while the electric field for r≤R requires a different approach using the defined charge density. Key calculations include determining the maximum electric field and its corresponding radius.

PREREQUISITES
  • Understanding of Gauss's Law: Flux = ∫E dot dA = Qencl/ε0
  • Familiarity with electric field equations, specifically E = k*(q/r^2)
  • Knowledge of spherical coordinates and volume integrals
  • Basic calculus for integration of charge density over a volume
NEXT STEPS
  • Learn how to perform volume integrals in spherical coordinates
  • Study the derivation of electric fields from charge distributions
  • Explore the implications of Gauss's Law in nonuniform charge distributions
  • Investigate graphical representation of electric fields as functions of distance
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in advanced applications of Gauss's Law in electrostatics.

kbwelch17
Messages
7
Reaction score
0

Homework Statement



A nonuniform, but spherically symmetric, distribution of charge has a charge density ρ(r) given as follows:
ρ(r) = ρ0(1-r/R) for r≤R
ρ(r) = 0 for r≥R

where ρ0 = 3Q/∏R^3 is a positive constant.

(a.) Show that the total charge contained in the charge distribution is Q.
(b.) Show that the electric field in the region r≥R is identical to that produced by a point charge Q at r = 0.
(c.) Obtain an expression for the electric field in the region r≤R.
(d) Graph the electric field magnitude E as a function of r.
(e.) Find the value of r at which the electric field is maximum, and find the value of that maximum field.

Homework Equations



Gauss' Law : Flux = ∫E dot dA = Qencl/ε 0
Electric Field of a point charge: E = k*(q/r^2)

The Attempt at a Solution



I am really just having trouble setting up the integral. You would be integrating the electric field over a sphere, so you would need to choose dA (is this a slice of the area of the sphere?) and a formula to find electric field for a given r. In order to find the latter you would need to use Gauss' Law in which case a give r would give the electric field

ρ(r) = q /A1 (is this the area or the volume of the sphere in question?)
q = ρ(r)*A1

E*A2 (what area is this?)= q/ε0
E = ρ(r)*A1 / A2*ε0

There are a few things I am confused about in here so please feel free to ask me to clarify anything. I need to know if I am on the right track here.

Thanks!
 
Physics news on Phys.org
kbwelch17 said:

Homework Statement



A nonuniform, but spherically symmetric, distribution of charge has a charge density ρ(r) given as follows:
ρ(r) = ρ0(1-r/R) for r≤R
ρ(r) = 0 for r≥R

where ρ0 = 3Q/∏R^3 is a positive constant.

(a.) Show that the total charge contained in the charge distribution is Q.
(b.) Show that the electric field in the region r≥R is identical to that produced by a point charge Q at r = 0.
(c.) Obtain an expression for the electric field in the region r≤R.
(d) Graph the electric field magnitude E as a function of r.
(e.) Find the value of r at which the electric field is maximum, and find the value of that maximum field.

Homework Equations



Gauss' Law : Flux = ∫E dot dA = Qencl/ε 0
Electric Field of a point charge: E = k*(q/r^2)

The Attempt at a Solution



I am really just having trouble setting up the integral. You would be integrating the electric field over a sphere, so you would need to choose dA (is this a slice of the area of the sphere?) and a formula to find electric field for a given r. In order to find the latter you would need to use Gauss' Law in which case a give r would give the electric field

ρ(r) = q /A1 (is this the area or the volume of the sphere in question?)
q = ρ(r)*A1

E*A2 (what area is this?)= q/ε0
E = ρ(r)*A1 / A2*ε0

There are a few things I am confused about in here so please feel free to ask me to clarify anything. I need to know if I am on the right track here.

Thanks!
For part (a), you want to use ##dq = \rho\,dv## and integrate over the entire sphere to find the total charge. You don't use Gauss's law here.
 
  • Like
Likes   Reactions: 1 person

Similar threads

Replies
6
Views
2K
Replies
10
Views
4K
  • · Replies 11 ·
Replies
11
Views
2K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 7 ·
Replies
7
Views
4K
Replies
23
Views
5K
Replies
28
Views
5K
  • · Replies 12 ·
Replies
12
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K