How Does Halving the Radius Affect the Period in Centripetal Acceleration?

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SUMMARY

Halving the radius in a centripetal acceleration scenario results in a decrease of the period by a factor of 2, provided that the centripetal acceleration remains constant. The equations governing this relationship are a = V²/r for acceleration and T = 2πr/v for the period. When the radius is halved, the new period Tfinal can be calculated using Tfinal = 2π(½r)/u, where u is the new velocity required to maintain the same acceleration. This relationship highlights the direct impact of radius on the period of motion in centripetal systems.

PREREQUISITES
  • Centripetal acceleration concepts
  • Understanding of the equations a = V²/r and T = 2πr/v
  • Basic algebra for manipulating equations
  • Knowledge of velocity and its relationship to radius and period
NEXT STEPS
  • Explore the implications of varying centripetal acceleration on period
  • Learn about the effects of mass on centripetal motion
  • Investigate real-world applications of centripetal acceleration in engineering
  • Study the relationship between angular velocity and centripetal acceleration
USEFUL FOR

Physics students, educators, and professionals involved in mechanics or engineering who are looking to deepen their understanding of centripetal motion and its mathematical relationships.

smillphysics
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What happens to the period when you cut the radius in half for a centripetal acceleration problem?


a=V^2/r
T=2pi*r/v


I need some background on this question. I believe the answer is the period is decreased by a factor of 2. I am just slightly confused.
 
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Well, that would depend. Are you keeping the acceleration on the body the same?
If so, then the problem isn't quite as trivial:
ainitial = v²/rinitial
afinal = u²/rfinal
Tinitial = 2πr/v
Tfinal = 2π(½r)/u

Since we want the acceleration before we cut the radius in half to be the same as after, all that remains to find u and Tfinal is a simple equation.
 

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