How Does Hydrostatic Equilibrium Affect Star Pressure Calculation?

Click For Summary
SUMMARY

This discussion focuses on the relationship between hydrostatic equilibrium and star pressure calculations, specifically for stars with a density profile defined as ρ(r) = ρc(1 - (r/R)^a), where ρc is the core density and a = 2. The equations governing hydrostatic equilibrium and mass distribution are provided, including dP/dr = -ρ(r)Gm(r)/r² and dM/dr = ρ(r)4πr²dr. The challenge lies in satisfying both the power law density assumption and the boundary conditions, leading to the conclusion that the core pressure for neutron stars is significantly less than the relativistic pressure of (ρc²)/3.

PREREQUISITES
  • Understanding of hydrostatic equilibrium in astrophysics
  • Familiarity with differential equations and boundary conditions
  • Knowledge of stellar structure and density profiles
  • Basic concepts of neutron star physics
NEXT STEPS
  • Research the derivation of pressure equations in stellar models
  • Study the implications of different density profiles on star stability
  • Explore the calculations for neutron star core pressure using advanced equations
  • Investigate the relationship between mass, radius, and pressure in compact stars
USEFUL FOR

Astronomers, astrophysicists, and students studying stellar dynamics, particularly those interested in neutron stars and their pressure calculations.

dats13
Messages
12
Reaction score
0

Homework Statement


Assume a star is in hydrostatic equilibrium and that the density of the star is follows
\rho \propto \frac{1}{r^{a}}

where \r is the distance from the centre of the star and \r is a constant.

Derive an relation for the pressure of the star as a function of \r.

Homework Equations



Hydrostatic Equilibrium:
<br /> \frac{dP}{dr} = - \rho(r) \frac{G m(r)}{r^2} (1)<br />

Mass Equation:
<br /> \frac{\mathrm{d} M}{\mathrm{d} r}=\rho (r)4\pi r^{2} dr (2)<br />


The Attempt at a Solution


I am assuming that the following boundary conditions must be satisfied.

<br /> \rho(0) = \rho_c \; \; \; \rho(R) = 0<br />
<br /> m(0) = 0 \; \; \; m(R) = M_{tot}<br />

The problem that I run into is satisfying these equations with the assumption

\rho \propto \frac{1}{r^{a}}

If I assume
\rho(r) = \rho_c(1-(r/R)^{a})


then the boundary conditions are satisfied, but the power law assumption is not.

Once I get the suitable function for \rho, then I can solve Eq. (2) for the Mass as a function of r and then (1) to get a function for the pressure.

But I am unsure of how to satisfy both the power law and boundary conditions for \rho.

Any suggestions would be greatly appreciated.
 
Physics news on Phys.org
I think the best density profile (for a gas star and probably a neutron star) and the one worth solving for is ρ(r)=ρc(1−(r/R)a) with a=2. Using this I calculated ρc = 2.5M/V where M/V = average star density. So ρ(r)=2.5M(1−(r/R)2)/V. I think this should be used in the pressure integral. I'm interested in accurately calculating the core pressure for neutron stars and theoretical compact gas stars. I want to show that neutron star core pressure is significantly less than ρ(c)2. Anybody there?
 
Rewrite using different format: I think the best density profile (for a gas star and probably a neutron star) and the one worth solving for is ρ = ρc(1−(r/R)^a) where ρc = core density and a = 2. Using this I calculated ρc = 2.5M/V where M/V = average star density. So ρ = 2.5M[1−(r^2/R^2)]/V. I think this should be used in the pressure integral. I'm interested in accurately calculating the core pressure for neutron stars and theoretical compact gas stars. Probably neutron star core pressure at collapse is less than relativistic pressure of (ρc^2)/3. Anybody there?
 
The OP has graduated. Thread closed.
 

Similar threads

Replies
6
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
Replies
5
Views
2K
Replies
1
Views
2K
  • · Replies 11 ·
Replies
11
Views
4K
Replies
2
Views
2K
  • · Replies 14 ·
Replies
14
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K