How Does Impulse Affect Particle Velocity?

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SUMMARY

The discussion focuses on calculating the final velocity of a particle after a force has been applied. Initially, the particle has a velocity of -6.3 m/s and a mass of 5.2 kg. The impulse applied to the particle is 42 Ns, leading to the equation j = Δp, where Δp equals the change in momentum. The final velocity (vF) is determined to be 1.777 m/s after applying the impulse.

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DollarBill
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Homework Statement


http://img401.imageshack.us/img401/46/impulsemw6.jpg

Before the force is applied (t<0), the particle moves along the x-axis with a velocity of -6.3 m/s.

Find the velocity of the particle after the force stops acting on it.

The particle has a mass of 5.2 kg

Homework Equations


j=\Deltap
\Deltap=0

The Attempt at a Solution


j=42Ns

j=\Deltap
42=mvF-mv0
42=(5.2)vF-5.2(-6.3)
9.24=5.2(v)F
vF=1.777 m/s
 
Last edited by a moderator:
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Your method looks good.
 

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