How Does Light Emerge from a Prism Using Snell's Law?

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PeachBanana
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Homework Statement



Light is incident on an equilateral glass prism at a 45.0 °angle to one face. Calculate the angle at which light emerges from the opposite face. Assume that n = 1.49.
θ4 = ?

Homework Equations



n1 * sin θ1 = n2 * sin θ2

The Attempt at a Solution



n1 = 1.00 (air)
n2 = 1.49
sin 45° = 0.707

n1 * sinθ1 / 1.49 = sin θ2

sin θ 2 = 0.474
θ2 = 28.33°

I'm having trouble finding θ3.

n2 = 1.49
θ2 = 28.33°
n3 = 1.49
θ3 = ??
 
Attachments
  • Ray diagram of a light ray entering an equilateral prism at 45.0 degrees from the normal, refracting toward the normal, crossing the prism, and emerging from the far face; labels show theta 2, theta 3 and the emergence angle marked as ? = theta 4.
    GlassPrism.jpg
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Last edited:
I suggest that you draw a diagram. Then knowing the angle you just found, you can calculate the angle at which the light is incident from glass to air at the second face of the prism.
Then use the same method as before.