How Does Mass and Height Affect the Angular Speed of a Rotating Bicycle Wheel?

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The discussion focuses on determining the angular speed of a bicycle wheel when a mass falls a distance h. The initial energy equation used is mgh = 1/2 mv^2 + 1/2 Iω^2, but the user struggles with incorporating the relationship between linear velocity and angular velocity. The correct approach involves substituting v with rω in the energy equation to express everything in terms of ω. The key takeaway is to ensure that the relationship between linear and angular motion is correctly applied to solve for the angular speed. Understanding these relationships is crucial for accurately calculating the wheel's angular speed after the mass falls.
PascalPanther
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"Consider the bicycle wheel is not turning initially. A block of mass m is attached (with a massless string) to a wheel. The block is allowed to fall a distance of h. Assume that the wheel has a moment of inertia I about its rotation axis.

Find the angular speed of the wheel after the block has fallen a distance of h in terms of m,g,h, r(of the wheel) and I"

This is what I did:

U + K + W(other) = U + K
mgh + 0 + 0 = 0 + 1/2mv^2 + 1/2 I*omega^2

omega = Sqrt[(2mgh - mv^2)/I]

This is wrong... what am I doing wrong? I know I can use omega = v^2/r, but not sure where that would go...
 
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PascalPanther said:
"Consider the bicycle wheel is not turning initially. A block of mass m is attached (with a massless string) to a wheel. The block is allowed to fall a distance of h. Assume that the wheel has a moment of inertia I about its rotation axis.

Find the angular speed of the wheel after the block has fallen a distance of h in terms of m,g,h, r(of the wheel) and I"

This is what I did:

U + K + W(other) = U + K
mgh + 0 + 0 = 0 + 1/2mv^2 + 1/2 I*omega^2

omega = Sqrt[(2mgh - mv^2)/I]

This is wrong... what am I doing wrong? I know I can use omega = v^2/r, but not sure where that would go...
ω = v^2/r is not correct, but it is sort of close. When you get it right, you can replace either v or ω using the correct relationship. Since you want to solve for ω, replace the v and solve away.
 
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