How Does Melting Ice Affect Global Entropy?

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SUMMARY

The melting of a 4.50 kg block of ice at 0°C in a 3.50°C ocean results in a significant change in global entropy. The entropy of the ice block is calculated using the latent heat of fusion (3.34x10^5 J/kg) and the absolute temperature (273.15 K), yielding an entropy change of 5502.47 J/K. The total entropy change for the system must account for both the melting of the ice and the subsequent temperature increase of the melted water. The energy required for these processes is derived from the ocean, which experiences a negligible temperature drop.

PREREQUISITES
  • Understanding of thermodynamics concepts, particularly entropy.
  • Familiarity with latent heat and specific heat capacity.
  • Knowledge of the equation dS = ∫dQ/T for calculating entropy changes.
  • Basic understanding of temperature scales, particularly Kelvin.
NEXT STEPS
  • Study the calculation of entropy changes in phase transitions, focusing on latent heat.
  • Learn about the specific heat capacity of water and its implications for thermal energy transfer.
  • Explore the concept of energy conservation in thermodynamic processes.
  • Investigate the effects of temperature changes in large bodies of water on global climate systems.
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Students studying thermodynamics, physics educators, and anyone interested in understanding the thermodynamic implications of phase changes in environmental science.

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Homework Statement



A 4.50 kg block of ice at 0 C falls into the ocean and melts. The average temperature of the ocean is 3.50 C, including all the deep water. By how much does the melting of this ice change the entropy of the world?

Homework Equations



Not sure if I should be using any equations as such, I've just been multiplying known values to get the energy, temperature and mass of the water and ice.

The Attempt at a Solution



I googled the mass of all water in the Earth's oceans, and got a figure of 7.61x10^23 kg, so I multiplied the specific heat capacity of water (4190 J/kg.K) by this mass to try and get the entropy of all the water, so I got 3.19x10^23 J/K.

I then got the entropy of the ice block by multiplying the latent heat of fusion of ice (3.34x10^5 J/kg) by the mass of the block and dividing it by the absolute temperature of the ice (273.15 K), giving what I thought was the entropy of the block to be 5502.47 J/K.

Obviously, because the two numbers are on completely different scales, adding/subtracting them makes almost no difference to the answer, so I've really no idea how to handle the question from here on!

All help is appreciated!
 
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Tw0 things happen to the water in the ice. First the ice melts, and then the water in the ice that melted changes temperature.

How is the entropy change for the second process calculated?

Does the temperature of the ocean change? From where does the energy come that melts the ice and raises its temperature?
 
"How is the entropy change for the second process calculated?"

Not sure how to calculate ANY entropy process, the textbook I have here (Sears and Zemansky's University Physics) gives me an equation dS = ∫dQ/T, where S is the entropy, Q is the heat energy and T is the absolute temperature, but I'm not sure how to apply that to what I have, I guess the ice block's temperature changes to the 3.5 C, but then where do I get the dQ value?

"Does the temperature of the ocean change? From where does the energy come that melts the ice and raises its temperature?"

I assume the temperature of the ocean drops SLIGHTLY, but I can't imagine it drops by any noticeable amount? Surely the energy comes from the slightly warmer ocean?
 
jfislove said:
but then where do I get the dQ value?

From the definition of specific heat.
 

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