How Does Momentum Affect the Motion of a Boat When People Jump Onboard?

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The discussion centers on the application of momentum conservation in a scenario involving a 200 kg canoe and three individuals jumping onboard. When the first man, weighing 60 kg, jumps into the canoe at 5 m/s, and the second man, weighing 70 kg, jumps at 8 km/s, their combined momentum affects the canoe's speed. The final speed of the canoe, after both jumpers come to rest relative to it, must be calculated considering the conservation of momentum, despite the negligible friction between the canoe and water. The third individual, weighing 80 kg, walking at 2 km/s further complicates the scenario, but the principle of momentum conservation remains the key to solving the problem.

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A 200 kg canoe lies at rest in the water, near a dock but untethered. Any
friction between the canoe and the water is negligible. A 60 kg man runs along the
dock toward the boat and jumps in, at velocity v = 5 m/s (directed toward the long
dimension of the canoe). The coefficient of friction between his shoes and the boat
floor is µk = 0.3, µs = 0.5; he slides along the boat floor and comes to rest relative to
the boat. His 70 kg friend does the same thing, jumping with v = 8 km/s, and with
µk = 0.1, µs = 0.8 (he has different shoes). After they come to a stop in the boat, a
third person with m = 80kg, who was at the opposite end of the boat, begins to walk
toward them, at v = 2km/s relative to the ground. What is the speed of the boat
(relative to the ground) at this time, when the two jumpers are at rest relative to the
boat, and the third person has begun walking?

Is friction relevant? How do you calculate the final speed?
 
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If this is a homework question, there's another forum for that. Anyway, you should present your own attempt at a solution.
I believe momentum will be conserved.
 

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