How Does Opening a Parachute Affect a Falling Parachutist's Motion?

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SUMMARY

The discussion focuses on the physics of a parachutist's motion upon opening a parachute. The parachutist, with a mass of 70 kg, experiences a downward gravitational force of 686 N and an upward air resistance force of 895 N. The net acceleration calculated is 3.0 m/s² upwards, which is confirmed as correct. However, the participant incorrectly calculated the distance fallen in 5.0 seconds, arriving at 226.4 m instead of the correct 150 m due to misapplication of initial velocity and acceleration values.

PREREQUISITES
  • Understanding of Newton's Second Law (Fnet = ma)
  • Knowledge of kinematic equations (d = v1t + 1/2at²)
  • Basic concepts of forces including gravity and air resistance
  • Ability to convert units (e.g., km/h to m/s)
NEXT STEPS
  • Review kinematic equations for motion under constant acceleration
  • Study the effects of air resistance on falling objects
  • Learn about free fall and terminal velocity concepts
  • Practice problems involving forces and motion in physics
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Students studying physics, particularly those focusing on mechanics and motion, as well as educators seeking to clarify concepts related to forces and acceleration in free fall scenarios.

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Homework Statement


A parachutist of mass 70kg, in free fall at 136 km/h, opens a parachute. if the chute creates a 895 N air resistance force and the parachutist is being pulled down by a force of gravity at 686 N
a) find hte acceleration of the parachutist
b) how far does she fall in 5.0 s?

Homework Equations


Fnet = ma, d = v1t + 1/2at^2

The Attempt at a Solution


First i determined part A and i got the answer 3.0 m/s^2 [up]. which is correct in the answer key.
then i used the equation d = v1t + 1/2at^2, converting 136 km/h to m/s
d = v1t + 1/2at^2
d = 37.7 m/s(5s) + 1/2(3 m/s^2)[(5s)^2]

and i got 226.4 m. the correct answer is 150m. i don't know what i did wrong. i then tried using the acceleration due to gravity, 9.81 m/s^2 because it is a freefall but the answer was still wrong.
please help!
 
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The person's initial speed is downward, thus negative.
 

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