How Does pH Affect Peptide Separation in Electrophoresis?

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The optimal pH for electrophoresis separation of two peptides with isoelectric points (pI) of 10.3 and 7 is crucial for effective migration. At a pH above 10.3, the peptide with a pI of 10.3 will carry a positive charge, while the peptide with a pI of 7 will be negatively charged at pH 8 or 10. This charge difference enhances separation, as oppositely charged peptides migrate towards their respective electrodes. Maintaining a pH that ensures the peptides have opposite charges is essential for achieving the best separation during electrophoresis. Understanding the relationship between pH and peptide charge is key to optimizing electrophoretic techniques.
Melow
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Hi all, I have a question about this exercise:

Which is the best option of pH for electrophoresis separation of two peptides with isoelectric points of 10.3 and 7 respectively? The given options of pH are 3,8 or 10.

I've thought that if pH is more than 7, then, there will be positive charge for the peptide of 10.3 pI, and negative charge for the peptide of 7 pI, but i don't know how to manage th sign of the charges to get the best eletrophoresis separation. Is it better to have both of them with the same charge or the opposite charge?

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How does the sign of the charge influence how the peptides migrate during electrophoresis?
 

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