How Does Plaque Constriction Affect Blood Velocity in Arteries?

Click For Summary
SUMMARY

The discussion focuses on the impact of plaque constriction on blood velocity in arteries, specifically analyzing a scenario where an artery with a 3 mm radius is partially blocked, resulting in an effective radius of 2 mm and an average blood velocity of 0.5 m/s. The calculated average velocity in the unobstructed region is 0.22 m/s, derived using the Hagen-Poiseuille equation, which relates flow rate to pressure drop, viscosity, and radius. The participants express confusion regarding the flow rate dynamics, particularly the relationship between velocities in different sections of the artery.

PREREQUISITES
  • Understanding of fluid dynamics principles, specifically the Hagen-Poiseuille equation.
  • Knowledge of blood flow continuity and the equation rho1*A1*V1=rho2*A2*V2.
  • Familiarity with concepts of laminar flow in circular tubes.
  • Basic understanding of pressure drop (ΔP) and its effects on flow rate.
NEXT STEPS
  • Study the Hagen-Poiseuille equation in detail to understand its applications in fluid dynamics.
  • Learn about blood flow continuity and how to apply the equation rho1*A1*V1=rho2*A2*V2 in various scenarios.
  • Research the effects of arterial plaque on hemodynamics and blood velocity changes.
  • Explore advanced topics in fluid mechanics, particularly in relation to laminar and turbulent flow transitions.
USEFUL FOR

This discussion is beneficial for students in biomedical engineering, medical professionals studying cardiovascular dynamics, and researchers focusing on hemodynamics and arterial health.

semitope
Messages
2
Reaction score
0

Homework Statement



An artery with a 3 mm radius is partially blocked with plaque. In the constricted region the effective radius is 2 mm and the average blood velocity is 0.5 m/s. What is the average velocity in the unobstructed region? Assume no changes to η, L, and ΔP. Ans; 0.22 m/s

Homework Equations



Flow rate = ΔP(π/8)(1/η)(R^4/L)
= (PA– PB)(π/8)(1/η)(R^4/L)


The Attempt at a Solution



rate = [(ΔPπ)/8ηL] * R^4

Turned the middle section into x and solved for x. then used x to get the flow rate with a diameter of 3mm. I got something around 2.5m/s. Doesn't seem right, but at the same time the answer given by the professor doesn't seem right either. the flow rate in the larger vessel is less than that in the obstructed portion if that answer is correct. If the 0.22 is correct I'd love an explanation of how it is solved
 
Physics news on Phys.org
rho1*A1*V1=rho2*A2*V2 which is basic flow continuity

Therefore V2=(A1/A2)*V1

Area is proportional to square of radius.
 
Thanks. Would what I was doing have worked if the systems were separate with the same parameters but different radii?
 
You have the Hagen-Poiseuille equation that relates pressure drop to discharge in a circular tube of length L for laminar flow. The problem is that whenever the velocity changes, the pressure changes so parameters do not remain the same.
 
Last edited:

Similar threads

Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
6K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
0
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
8K
  • · Replies 1 ·
Replies
1
Views
7K