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- Homework Statement
- A viscous fluid with viscosity η = 1.7 × 10^-3 Pa s is flowing horizontally in the pipe shown below. Section 1, 2, and 3 have radii of r1 = 10.0 cm, r2 = 8.0 cm, and r3 = 6.0 cm, respectively. All sections have the same length L = 8.1 m. The volume flow rate of the fluid in Section 1 is F1 = 0.063 m^3/s. The pressure differences across Section 2 and Section 3 are both 41 PA because these two split sections are parallel, just as in the DC circuit.

{I am given a diagram with a single pipe splitting into two pipes, flow arrows all pointed to the right, with the L sections being the flat horizontal areas, L sections not including the distance.}

(a) What is the speed of the fluid in Section 1?

(b) What is the volume flow rate in Section 2?

(c) What is the speed of the fluid in Section 2?

(d) What is the speed of the fluid in Section 3?

- Relevant Equations
- Volume Flow Rate(VFR) = Cross-sectional Area multiplied by Velocity (A*v)

[VFR=Av]

and/or

Volume Flow Rate = viscosity (η) times velocity (v) times cross-sectional area (A) all divided by length (L)

[VFR=ηvA/L]

Continuity Equation: A1V1=A2V2

where one area times velocity equaled another area times velocity

In my first attempt, I started off converting the radii of all three sections from centimeters (10, 8, 6) to meters (0.10 , 0.08 , 0.06), then used the VFR=Av formula to find the speed/velocity of section one.

VFR== 0.063 m^3/s

A== pi*r^2=pi*(10cm)^2=pi*(0.10)^2=pi*0.01 == 0.031415927

VFR/A=v ==2.005352283...

Where my attempts began to change was for the second (b) question. I originally went for just plugging the velocity found in question one with a different area, then moving on to question b -- but then trying to reverse-engineer to get question c, I just got the velocity I borrowed earlier.

VFR=(pi*(0.08)^2)v

v=2.005352283...

VFR=0.04032

{then reversed for the same thing due to using the same velocity as question a}

This pinged as a mental red flag for me, and so I went to the internet to search. While searching for possible other ways to solve for this, I was reminded of the continuity equation. So, using that to answer the second question by saying the volume flow rate for section 1 was equal to the VFR for section 2, I then moved to question 3 by saying the following:

VFR == 0.063 m^3/s

A==(pi*0.08^2)=(pi*0.0064)=0.020106193...

VFR/A=v == 3.133362942121689...

I tried, after getting both attempts at a third question (c) answer, to figure out if I needed continuity or something else for question 4, but I'm honestly stuck.

I tried to get a tutor to help me confirm if I did this right, and they gave me the second VFR equation to redo the first question with. The velocity number for the redo was 3001.764705882353, and with that being such a large number, I felt like it couldn't be correct.

I'm not sure if I was ever on the right track, or if all of these attempts are wrong. Please help.

VFR== 0.063 m^3/s

A== pi*r^2=pi*(10cm)^2=pi*(0.10)^2=pi*0.01 == 0.031415927

VFR/A=v ==2.005352283...

Where my attempts began to change was for the second (b) question. I originally went for just plugging the velocity found in question one with a different area, then moving on to question b -- but then trying to reverse-engineer to get question c, I just got the velocity I borrowed earlier.

VFR=(pi*(0.08)^2)v

v=2.005352283...

VFR=0.04032

{then reversed for the same thing due to using the same velocity as question a}

This pinged as a mental red flag for me, and so I went to the internet to search. While searching for possible other ways to solve for this, I was reminded of the continuity equation. So, using that to answer the second question by saying the volume flow rate for section 1 was equal to the VFR for section 2, I then moved to question 3 by saying the following:

VFR == 0.063 m^3/s

A==(pi*0.08^2)=(pi*0.0064)=0.020106193...

VFR/A=v == 3.133362942121689...

I tried, after getting both attempts at a third question (c) answer, to figure out if I needed continuity or something else for question 4, but I'm honestly stuck.

I tried to get a tutor to help me confirm if I did this right, and they gave me the second VFR equation to redo the first question with. The velocity number for the redo was 3001.764705882353, and with that being such a large number, I felt like it couldn't be correct.

I'm not sure if I was ever on the right track, or if all of these attempts are wrong. Please help.