How does potential energy increase, if height increases?

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SUMMARY

The discussion focuses on the relationship between height and gravitational potential energy (PE) using two formulas: PE = -GMm/r and PE = mgh. It highlights a common misconception that potential energy decreases with increasing height, as illustrated by calculations with mass values M=50, m=5, and varying heights. The key takeaway is that while the gravitational potential energy appears to decrease in certain contexts, this is due to the choice of reference point for zero potential energy. The negative sign in the gravitational potential energy formula is crucial for understanding the behavior of energy as two masses approach each other.

PREREQUISITES
  • Understanding of gravitational potential energy concepts
  • Familiarity with the formulas PE = -GMm/r and PE = mgh
  • Basic knowledge of gravitational fields and field strength
  • Ability to perform algebraic manipulations and approximations
NEXT STEPS
  • Study the derivation and implications of the gravitational potential energy formula PE = -GMm/r
  • Learn about the concept of reference points in energy calculations
  • Explore the approximation techniques for small values in physics
  • Investigate the differences between gravitational potential energy in varying gravitational fields
USEFUL FOR

Students of physics, educators explaining gravitational concepts, and anyone interested in the nuances of potential energy calculations in gravitational fields.

sawer
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(constants're ommitted)

1-) M=50, m=5, h=5 then Potential Energy = (50*5)/5 = 50

After increasing height

2-) M=50, m=5, h=10 then Potential Energy = (50*5)/10 = 25

Field strength decreases amount of h^2 so according to formulas potential energy decreases as h increases.

But that mustn't be true. But as I showed according to Potential energy and Field strength formulas, potential energy decreases as h increases. What is wrong here?
 
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In that format, the gravitational PE is negative:

##PE = -\frac{GMm}{r}##

Alternatively, for a constant gravitational field, you can have:

##PE = +mgh##
 
sawer said:
(constants're ommitted)

1-) M=50, m=5, h=5 then Potential Energy = (50*5)/5 = 50

After increasing height

2-) M=50, m=5, h=10 then Potential Energy = (50*5)/10 = 25

Field strength decreases amount of h^2 so according to formulas potential energy decreases as h increases.

But that mustn't be true. But as I showed according to Potential energy and Field strength formulas, potential energy decreases as h increases. What is wrong here?

If you write things in the form that you have: V = -G m_1*m_2/r -- there is a very important negative sign that you lost, which you need to keep. What this does is ensure that the potential energy of two bodies at infinite separation is equal to zero, and that as the bodies come together, the potential energy is lowered (more negative). You could tell that you had made a mistake, because as you increased the height, the potential energy went down.

In the other common way of looking aqt things, close to the Earth's surface, you are using the simple approximation that V = m * g * h. In using this, you have done a number of things. One, you have redefined the zero of energy -- completely ok to do -- as being at the surface of the Earth ==> V = 0 when h = 0. You have also changed the relationship between distance. In the first case, the answer is proportiional to 1/r, in the second case, it is proportional to h.

Can you show how both of these expressions could possibly be true? Hint: Use the first expression, and let r = Re + h, where Re is the radius of the earth. Use an approximation for 1/(1+x), that is valid for small x (x<<1)
 

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