How Does Pressure Difference Determine Fluid Density?

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To determine the density of a fluid using pressure difference, the formula ΔP = ρgh is applied, where ΔP is the pressure difference, ρ is the fluid density, g is the acceleration due to gravity, and h is the height of the fluid column. In this case, the pressure at the top of the box is 109.4 kPa, and at the bottom, it is 112.0 kPa, resulting in a pressure difference of 2.6 kPa. The height of the box is 0.25 m (25 cm), allowing for the calculation of fluid density by rearranging the formula to ρ = ΔP / (gh). Understanding this relationship helps in solving fluid density problems effectively.
drewsteriam
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Ok here goes,
A cubical box 25.00 cm on each side is immersed in a fluid. The pressure at the top surface of the box is 109.4 kPa and the pressure on the bottom surface is 112.0 kPa. What is the density of the fluid.

I know density=mass/volume and I know my teacher gave us another long formula in class that I never understood so that is about all I know about these problems.

My attempt at a solution: I don't even know what the problem is asking so I don't have much of an attempt at it. If anyone could explain the concept to me and/or let me know of some formulas that might help me that would be great. Thanks
 
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What is the density of the fluid.

The change in pressure is simply \rhogh, where \rho is the fluid density and h is the differential height over which the pressure difference is measured.

http://hyperphysics.phy-astr.gsu.edu/hbase/pflu.html

So knowing the pressure at bottom is 109.4 kPa and at top the pressure is 112.0 kPa, equate the difference to \rhogh.
 
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