How Does Recoil Affect the Character in Diamonds Are Forever?

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Homework Help Overview

The discussion revolves around a physics problem related to recoil in the context of the movie Diamonds Are Forever. It involves calculating the recoil velocity of a character after firing a gun, using principles of conservation of momentum.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the conservation of linear momentum to determine the recoil velocity but expresses confusion regarding the force and the appropriate mass to use in the calculations. Some participants suggest focusing solely on momentum rather than force.

Discussion Status

Participants have provided guidance emphasizing the use of conservation of momentum, indicating that the total momentum before and after firing must remain zero. The original poster has indicated progress in solving the problem after receiving feedback.

Contextual Notes

The original poster mentions confusion regarding the wording of the problem and the specific masses to consider for the calculations. There is also a note about urgency in seeking help.

cheechnchong
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The lead female character in the movie Diamonds Are Forever (lol so random) is standing at the edge of an offshore oil rig. As she fires a gun, she is driven back over the edge and into the sea. Suppose the mass of a bullet is 0.010 kg and its velocity is +720 m/s. Her mass (including the gun) is 51 kg. (a) What recoil velocity does she acquire in the response to a single shot from a stationary position, assuming that no external force keeeps her in place? (b) Under the same assumption, what would be her recoil velocity if, instead, she shoots a blank cartridge that ejects mass of 5.0 x 10^-4 kg at a velocity of +720 m/s?

My Conflict- Well, I'm stuck on finding the Force and the wording on which mass to use is confusing (for parts A and B)...The equation I am using is
Force x Time = Change Velocity x Mass -- This problem has something to do with Conservation of Linear Momentum. If you're trying to work this problem out, then the answer you should get for Part B is .0071 m/s. Anyways, PLEASE HELP...I need help ASAP! :confused: :confused:
 
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You don't need the force. All you need is conservation of momentum. Before the bullet is fired, there is zero momentum. After it is fired the total momentum of the bullet plus the girl must still be zero.
 
OlderDan said:
You don't need the force. All you need is conservation of momentum. Before the bullet is fired, there is zero momentum. After it is fired the total momentum of the bullet plus the girl must still be zero.

ok i will try it out and let you know in a bit! thanks buddy :smile:
 
Last edited:
^^^Hey, I got the answer right after the server crashed lol thanks!
 

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