How Does Reducing Earth's Gravity Affect the Time a Thrown Ball Takes to Return?

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SUMMARY

The discussion centers on the effect of reducing Earth's gravity from g to g/6 on the time it takes for a thrown ball to return to the thrower. The initial reasoning presented by the user Gear2d correctly concludes that the time increases by a factor of 6 due to the decrease in acceleration. However, the user initially used an incorrect equation for projectile motion. The correct equation to apply in this scenario is v² - v₁ = at, which clarifies the relationship between velocity, acceleration, and time in this context.

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  • Familiarity with kinematic equations, particularly v² - v₁ = at.
  • Knowledge of gravitational acceleration and its effects on motion.
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  • Study the kinematic equations in detail, focusing on their applications in projectile motion.
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Gear2d
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Homework Statement


If I throw a ball straight up to a height h with velocity v and it takes the ball time t to go up and back to my hands, by how much would time increase or decrease if gravity on Earth where changed from g to g/6?

Homework Equations



v = a*t

The Attempt at a Solution



I wanted make sure what I am thinking was correct. I thought about this problem as a projectile problem and said that t = (v*sin(theta))/a, where "a" is acceleration. Now since the ball was thrown straight up, I made sin(theta) to sin(90). So the problem comes out to be t=v/a, and since "a" decreases by a factor of 6 that means time increase by a factor of 6. Would this reasoning be the correct way to do it?
 
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Gear2d said:
v = a*t

Hi Gear2d! :smile:

Your reasoning and your result are right … but your initial equation is wrong.

The general equation is v2 - v1 = at …

so what do you think it is in this particular case? :smile:
 

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