How Does Temperature Affect the Diameter of a Hole in an Aluminum Plate?

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SUMMARY

The discussion focuses on the thermal expansion of aluminum, specifically how temperature affects the diameter of a hole in an aluminum plate. At 22.00 degrees Celsius, the hole measures 1.179 cm, and the diameter at 199 degrees Celsius can be calculated using the formula ∆L = alpha L(0) ∆T. For Part B, the user correctly manipulates the equation to find the final temperature when the diameter is reduced to 1.177 cm, confirming that their method is accurate.

PREREQUISITES
  • Understanding of thermal expansion principles
  • Familiarity with the equation ∆L = alpha L(0) ∆T
  • Knowledge of the coefficient of linear expansion for aluminum
  • Basic algebraic manipulation skills
NEXT STEPS
  • Research the coefficient of linear expansion for aluminum
  • Learn how to apply thermal expansion equations in practical scenarios
  • Explore the effects of temperature on different materials
  • Investigate real-world applications of thermal expansion in engineering
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Students studying physics or engineering, particularly those focusing on material science and thermal dynamics, as well as professionals involved in manufacturing or construction where material expansion is a concern.

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Homework Statement


A hole in an aluminum plate has a diameter of 1.179 cm at 22.00 degrees Celsius.
Part A asks for the diameter of the hole at 199 degrees Celsius.?
Part B asks for the temperature of the hole when its diameter is 1.177 cm?


Homework Equations



∆L = alpha L(0) ∆T

The Attempt at a Solution


I got the answer for Part A.

Here's what I did so far for Part B:
I manipulated the equation as follows:
∆L/alpha*L(0) + Temp (initial) = Temp (final)

And I used the difference between 1.177 and 1.179 cm for ∆L, used 1.179 for L(0) and the 22 degrees C for the initial temperature. Is this method correct?
 
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