How Does Temperature Affect the Density of an Object?

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SUMMARY

The discussion focuses on calculating the density of an object at different temperatures, specifically from 10°C to 25°C, using the coefficient of linear expansion. The object has an initial density of 1250 kg/m³ and a linear expansion coefficient of α = 2.5 × 10⁻⁵ 1/K. The correct density at 25°C is determined to be 1248.6 kg/m³ using the formula V(T)=(1+β(Δt))V0, while the equation V=βV0ΔT is clarified as applicable only for volume change, not for direct volume calculations.

PREREQUISITES
  • Understanding of density and its units (kg/m³)
  • Familiarity with the concept of linear expansion and its coefficient (α)
  • Knowledge of algebraic manipulation for solving equations
  • Basic principles of thermodynamics related to temperature and volume
NEXT STEPS
  • Study the relationship between temperature and density in fluids and solids
  • Learn about volumetric thermal expansion and its applications
  • Explore the derivation and applications of the coefficient of linear expansion
  • Investigate the differences between linear and volumetric expansion equations
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Students in physics or engineering, educators teaching thermodynamics, and anyone interested in material properties related to temperature changes.

Patricia Reid
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Homework Statement


An object has a density of 1250 kg /m3 at 10C and a coefficient of linear expansion of α = 2.5 × 10−5 1 /K . What is the object’s density when the temperature is 25C?

Homework Equations


V=βV0ΔT
V(T)=(1+β(Δt))V0

The Attempt at a Solution


How I got the answer is that I used V(T)=(1+β(Δt))V0 and substituted v=m/ρ and after some algebra gave me the correct answer of 1248.6 kg/m2

When I used the first equation I listed I didn't get the correct answer... I was just wondering what the difference is in the equations and when to use themThanks in advance!
 
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The first equation is not for the volume, it is for the change of volume. You can see this by inserting zero temperature difference (you will get zero and not the volume).
 

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