How Does Tension Affect Energy Conservation in a Pendulum System?

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Homework Help Overview

The discussion revolves around the effects of tension on energy conservation in a pendulum system, focusing on the relationships between potential and kinetic energy as the pendulum swings.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of free body diagrams and the application of force equations. Questions arise regarding the definitions and relationships of variables such as gravitational potential energy and kinetic energy. There is also exploration of conservation laws and their relevance to the problem.

Discussion Status

The discussion is active with participants providing insights and clarifications. Some have made attempts to define energy changes within the system, while others are questioning the assumptions and definitions used in the equations presented.

Contextual Notes

Participants note the absence of external forces and the implications for energy conservation, as well as the potential confusion surrounding variable notation in the equations discussed.

Auburn2017
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Homework Statement


Refer to figure.

Homework Equations


U=Fs
T=.5mv^2
Vg=mgh

The Attempt at a Solution


I am not exactly sure where to start. I would appreciate if someone could nudge me in the right direction and then go from there.
 

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Start with a free body diagram of the mass when theta is 180. Write out the ΣF=ma equation for it.
 
haruspex said:
Start with a free body diagram of the mass when theta is 180. Write out the ΣF=ma equation for it.
I have done that but I am not sure how to get the velocity of the mass...
 

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Auburn2017 said:
I have done that but I am not sure how to get the velocity of the mass...
Your diagram seems to be for theta = 90 degrees.

For the velocity, any conservation law come to mind?
(In your 'relevant equations', I don't understand Vg=mgh. What is Vg there?)
 
haruspex said:
Your diagram seems to be for theta = 90 degrees.

For the velocity, any conservation law come to mind?
(In your 'relevant equations', I don't understand Vg=mgh. What is Vg there?)
yeah my figure is incorrect. Vg is the gravitational potential energy
 
Auburn2017 said:
yeah my figure is incorrect. Vg is the gravitational potential energy
Ok. I thought it more usual to use E or U for energy. What is the T in the preceding equation? Well, I can guess from the equation what it is, but why 'T'?
 
haruspex said:
Ok. I thought it more usual to use E or U for energy. What is the T in the preceding equation? Well, I can guess from the equation what it is, but why 'T'?
kinetic energy. it's just the notation we use.
 
Auburn2017 said:
kinetic energy. it's just the notation we use.
Ok, so what relates that to Vg?
 
haruspex said:
Ok, so what relates that to Vg?
U=ΔT-ΔV where V=Vg+Ve and Ve is the elastic potential energy(spring) but it isn't applicable to this problem
 
  • #10
Auburn2017 said:
U=ΔT-ΔV where V=Vg+Ve and Ve is the elastic potential energy(spring) but it isn't applicable to this problem
Let's investigate that. No spring here, so Ve is zero. What is U? Can you assign a value to it?
 
  • #11
U=ΔE=(T2-T1)+(VG2-VG1)
 
  • #12
Auburn2017 said:
U=ΔE=(T2-T1)+(VG2-VG1)

That's right.
What is the value of ΔE? In other words, does any energy enter or exit the system? (you are expected to assume the nudge does not add any kinetic energy to the pendulum).
 
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  • #13
billy_joule said:
That's right.
What is the value of ΔE? In other words, does any energy enter or exit the system? (you are expected to assume the nudge does not add any kinetic energy to the pendulum).
There are no external forces so now work is done on the system causing E=0. I figured out how to work in on my own. Thank you for your reply.
 

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