How Does Tension in a String Behave in Zero Gravity?

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Oblio
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an astronaut in gravity free space is twirling a mass m on the end of a string of length R in a circle, with constant angular velocity. Write down Newtons second lasw in polar coordinates and find the tension of the string.


What makes up F(t) without acceleration and gravity? I'm confused.
 
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There might not be gravity, but there's certainly acceleration. (Hint: Circular motion.)
 
I see that the net force can be written as:

F = F[tex]_{r}[/tex] [tex]\widehat{r}[/tex] + F[tex]_{\phi}[/tex] [tex]\widehat{\phi}[/tex]

So I believe my tension force is just F[tex]_{r}[/tex] ?

and N2L: F= m(F[tex]_{r}[/tex] [tex]\widehat{r}[/tex] + F[tex]_{\phi}[/tex] [tex]\widehat{\phi}[/tex]) ?

(for some reason my subscripts are appearing as superscripts)
 
Oblio said:
So I believe my tension force is just F[tex]_{r}[/tex] ?
OK. And since the angular velocity is constant, what's the tangential force?
 
I found in my text that

"F[tex]_{r}[/tex] would be the tension in the string and F[tex]_{\phi}[/tex] the force of air resistance retarding the stone in the tangential direction."

Do I need to account for air resistance in the tension or is it simply F[tex]_{r}[/tex]?
 
( On my computer anyways, subscripts are still appearing as superscripts, not sure why )
 
They are in free space--no air, no air resistance.

[tex]F_{r}[/tex] (F within tex brackets) versus F[tex]_{r}[/tex] (F outside of brackets)