How does the amount of charge on a doorknob affect the length of a spark?

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Homework Help Overview

The discussion revolves around the phenomenon of electric charge buildup when scuffing feet on a carpet, leading to a spark when touching a metal doorknob. The problem involves calculating the amount of charge accumulated based on the observed spark length and the breakdown field strength of air.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between charge, distance, and electric field strength, with attempts to apply relevant equations. Questions arise about the value of the Coulomb's constant (Kc) and its role in the calculations. There is also a discussion about the nature of charge transfer when scuffing feet on a carpet.

Discussion Status

Some participants have provided alternative values for Kc and discussed potential differences, while others express confusion over their calculations and the implications of the charge distribution between the finger and the doorknob. The conversation reflects a mix of interpretations and ongoing attempts to clarify the problem.

Contextual Notes

There is uncertainty regarding the correct interpretation of the spark length, with one participant questioning whether it should be 5 mm instead of 5 cm. Additionally, the lack of explicit values for Kc in the problem statement is noted as a constraint affecting the discussion.

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Homework Statement


On a dry winter day, if you scuff your feet across a carpet, you build up a charge and get a shock when you touch a metal doorknob. In a dark room you can actually see a spark about 5.0 cm long. Air breaks down at a field strength of 3.0 x 10^6 N/C. Assume that just before the spark occurs, all the charge is in your finger, drawn there by induction due to the proximity of the doorknob. Approximate your fingertip as a sphere of diameter 1.5 cm, and assume that there is an equal amount of charge on the doorknob 5.0 cm away.
How much charge have you built up?

Homework Equations


Q*Kc/r^2

The Attempt at a Solution


E > or equal 3*10^6
Knob)----d---(---R
2cm
(E*(d+r)^2)/kc=Q

Now I have several problems with this, first there's no value of Kc explicitly given to me. Our professor explicitly gives us Kc when it needs to be used to a certain decimal place. Secondly, I'm having an issue figuring out what exactly to do with my charge from the doorknob. My instinct tells me that both will be contributing to the charge equally but I can't seen to figure out where the distance of it and its charge would come into play with this problem. I'm thinking it has something with Kc not being used at all near the end solution but I'm not sure.

Any advice is appreciated, thank you.
 
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The 3*106 N/C is also 3*106 V/m

At 5cm then you know that the potential difference - thumb to knob must be 1/20th of that.

I'd simply use 8.99 * 109 for k in air.
 
Tried with 8e9 and got it returned as wrong so hrmm, still scratching away at this..

I've tried also to do this

Q=E(d+r)^2/kc (finger to any point where air breaks down)
Q=E(r)^2/kc (doorknob to any point where air breaks down)

Soo:

E(r)^2/kc=Q=E(d+r)^2/kc
But this ends up giving me units of meters alone so.. that won't work either
 
quick question: why is it when you scuff your feet, you lose electrons, instead of gain electrons from the carpet? Is it possible for it to go the other way?
 
Specialmias said:
On a dry winter day, if you scuff your feet across a carpet, you build up a charge and get a shock when you touch a metal doorknob. In a dark room you can actually see a spark about 5.0 cm long.
Surely they mean 5 mm here? :bugeye:
 

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