How Does the Center of Mass Move in a Block and Wedge System?

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In a block and wedge system on a frictionless surface, as a block slides down a rough inclined plane, the center of mass of the system moves both horizontally and vertically. The correct answer to the movement of the center of mass is that it moves vertically with increasing speed. The discussion highlights confusion regarding the application of momentum equations and the definitions of variables involved. Clarification is sought on the relationships between the masses and velocities in the context of the problem. Understanding the dynamics of the center of mass is crucial for solving this type of problem effectively.
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Homework Statement


A large wedge rests on a horizontal frictionless surface. A block starts from rest and slides down the inclined surface of the wedge, which is rough. During the motion of the block, the center of mass of the block and wedge.

a. does not move.
b. moves horizontally with constant speed.
c. moves horizontally with increasing speed
d. moves vertically with increasing speed
e. moves both horizontally and vertically

The correct answer was d.


Homework Equations


None given.


The Attempt at a Solution


I reasoned that since the block would begin to slide down the inclined plane, the center of mass of the entire system would shift in relation to the position of the block. Therefore, the center of mass should move both horizontally and vertically.
 
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Does the following make any sense?
 

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Spinnor said:
Does the following make any sense?

I'm missing some minus signs. m1v1 not equal m2v2 should read m1v1 not equal -m2v2 and m1v1 = m2v2 should read m1v1 = -m2v2
 
Thanks for helping :D
However, I still don't get it. What exactly is M_1, M_2 and V_1 and V_2 in this case, and how do the initial equations arrive at the conclusion through the arrows? Could you please elaborate? I kind of see how the math works, but I don't know how it arrives at the conclusions. Also, would you happen to know of another way to solve this problem? The test that I'm taking this from was supposed to be non-calculus based, so would you happen to know an algebraic way to solve it too?

Once again, thanks.
 
To answer the problem, you need to know how the CM is defined, and how the acceleration of the CM is related to the forces acting on the system.

ehild
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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