How Does the Commutator [p-hat_x, H-hat] Reveal Quantum Mechanics Fundamentals?

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Homework Help Overview

The discussion revolves around the commutator of the momentum operator and the Hamiltonian in quantum mechanics, specifically examining the expression [p-hat_x, H-hat] and its implications for understanding fundamental principles in quantum mechanics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the definition of the commutator and its application to the operators involved. Questions arise regarding the behavior of the Hamiltonian when combined with the momentum operator, particularly in terms of derivatives and the resulting expressions.

Discussion Status

Some participants have provided hints and guidance regarding the definition of the commutator and the treatment of derivatives. There is an ongoing exploration of how different terms behave under the operation of the commutator, with no explicit consensus reached yet.

Contextual Notes

Participants are navigating the complexities of operator algebra in quantum mechanics, particularly focusing on the implications of applying derivatives to various terms within the Hamiltonian. The discussion reflects the challenges of interpreting operator actions in this context.

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Homework Statement



by considering the action of [p-hat (subscript x), H-hat] on a general state, show that

[p-hat (subscript x), H-hat] =-ihbar dV/dx

Homework Equations



H-hat = (((p-hat)^2)/2m) +V(x)

p-hat (subscript x)= -i*h d/dx (partial derivative)


The Attempt at a Solution


tried lookin it up couldn't find anything
 
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It's right in front of you. Two hints:

1. What is the definition of the commutator of two operators? In other words, how would I write out [A, B]?

2. What is the derivative of a constant?
 
so the commutator is AB-BA

so it equals
i*h-bar d/dx(((p-hat)^2)/2m)+V(x)) -(((p-hat)^2)/2m)+V(x)) i*h-bar d/dx
=-ih-bar dV/dx ...
but why does -(((p-hat)^2)/2m)+V(x)) i*h-bar d/dx go to nothing? what do i do please, if the i*h-bar d/dx is put after the hamiltonian?
 
Last edited by a moderator:
what do i do please, if the i*h-bar d/dx is put after the hamiltonian?

In that case, you consider the derivative to be operating on 1 -- in other words d/dx = d/dx(1) = 0. So in the commutator, the only piece that doesn't vanish is the piece that features d/dx operating on a function of x -- which gives you -ih-bar dV/dx.
 

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