How Does the Displacement Equation Calculate Position Changes in Physics?

[-Physician]

We can have the velocity as v1 or v2 , time also, but In some cases i see it in displacement for e.x
$x=x_0+v_0 t + \frac{1}{2} at^2$, how can it be displacement 1 , displacement 2, can some one explain? Is it the displacement of the body 1, and displacement of the body 2 or what?

 

[Doc Al]

We can have the velocity as v1 or v2 , time also, but In some cases i see it in displacement for e.x
$x=x_0+v_0 t + \frac{1}{2} at^2$, how can it be displacement 1 , displacement 2, can some one explain? Is it the displacement of the body 1, and displacement of the body 2 or what?

In that version of the kinematic equation, x₀ is the initial position (at time t = 0), v₀ the initial velocity, and x is the position at time t.

 

[-Physician]

Wouldn't that be the length of the body, like if the length of the body is 5m and distance 10m, the displacement would be 5m?

 

[Doc Al]

Wouldn't that be the length of the body, like if the length of the body is 5m and distance 10m, the displacement would be 5m?

No. Kinematics describes the movement of a body, not its dimensions.