How Does the Gibbs-Helmholtz Equation Relate to Calculating Enthalpy?

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SUMMARY

The Gibbs-Helmholtz equation relates the change in Gibbs free energy (\(\Delta G\)) to enthalpy (\(\Delta H\)) and entropy (\(\Delta S\)) in thermodynamics. The equation is expressed as \(\left[\frac{d\left(\frac{\Delta G}{T}\right)}{\delta T}\right]_p = \frac{\Delta H}{T^2}\), indicating that enthalpy can be derived from the slope of a plot of \(\Delta G/T\) versus \(1/T\). This relationship is crucial for understanding chemical reactions and phase transitions in physical chemistry.

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neo2478
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Can somebody please shed a little light on what this formula represents in the physical world?
And how could I solve it to get \Delta H?

<br /> \left[\frac{d\left(\frac{\Delta G}{T}\right)}{\delta T}\right]_p = \frac{\Delta H}{T^2}<br />
 
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humm ..looks like entropia. Or may be I'm completely wrong.
 
So, you are saying that
<br /> \left[\frac{d\left(\frac{\Delta G}{T}\right)}{\delta T}\right]_p = \Delta S<br />
?
 
Last edited:
no i wrote that, but I'm not saying that :-).
Anyway should be something about Gibbs-Helmholtz equation, but i don't remeber much about it.
So something about chemistry and termodinamics application usually.

<br /> <br /> \left[\frac{\partial \Delta G}{\partial T}\right]_p = -\Delta S<br /> <br />

But wait a reply from someone that know of what is talking about because I'm not sure.
 
Gibbs Helmholtz
Note d(1/T)/dT is 1/T2. Solve for H. Cancel terms.
So Enthalpy can be obtained from plot of deltaG/T vs 1/T
 

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