How Does the Green Function Influence the Mean Value Theorem in Electrostatics?

Click For Summary
SUMMARY

The discussion focuses on the application of the Green function in demonstrating the Mean Value Theorem in electrostatics, specifically in charge-free space. The formula presented utilizes the Neumann boundary condition and includes terms for the electrostatic potential and Green's function, G_N. The user seeks clarification on whether the Green function can be treated as a constant on the boundary surface, which would simplify the integral calculations. The conversation emphasizes the importance of understanding Green functions in the context of electrostatics and boundary conditions.

PREREQUISITES
  • Understanding of electrostatic potential and the Mean Value Theorem.
  • Familiarity with Green's functions in mathematical physics.
  • Knowledge of Neumann boundary conditions in electrostatics.
  • Basic principles of Gauss's law and surface integrals.
NEXT STEPS
  • Study the properties and applications of Green's functions in electrostatics.
  • Learn about Neumann boundary conditions and their implications in potential theory.
  • Explore the derivation and application of Gauss's law in various electrostatic scenarios.
  • Review examples of the Mean Value Theorem in the context of potential theory.
USEFUL FOR

Students and professionals in physics, particularly those studying electrostatics, mathematical physics, or anyone needing a deeper understanding of Green functions and boundary value problems.

Locrian
Messages
1,881
Reaction score
256
I am demonstrating the mean value theorem, which says that for charge-free space the value of the electrostatic potential at any point is equal to the average of the potential over the surface of any sphere centered on that point. I have already found one way to do this, but would also like to show it using the following formula (which makes use of the Neumann boundary condition):

\Phi(X) = < \Phi > + \frac{1}{4\pi\epsilon_0} \int_V \rho(x')G_N(x,x') \,d^3x. +\frac{1}{4\pi}\int_S \frac{\partial\Phi}{\partial n'}G_N \,da

The first term on the right hand side is the average of the potential over the surface - so of course I expect the other two to be zero. The second is obviously zero. The third can be written as:

\frac{1}{4\pi}\int_S \nabla\Phi\cdot n' G_N \,da

\frac{1}{4\pi}\int_S (-E)\cdot n' G_N \,da

And I know the Green function is:

G(x,x') = \frac{1}{\mid x-x' \mid} + F(x,x')

\frac{\partial G_N}{\partial n'}(x,x') = -\frac{4\pi}{S}

for x' on S.

If I can argue G_N is constant then I can slide it out of the integral and happily use gaus' law to make the third term zero. But... I don't understand Green functions well.

That derivative is with respect to n. If I know that the Green function here is some constant on S, then the integral over that surface is also a constant on S. Is this true?

We have to do the problems in front of the class. The professor does not allow us to not understand what we are writing. Any help would be appreciated!
 
Physics news on Phys.org
Normally one sets the Green function to zero on the boundary of a 3D problem. Nice presentation of the question.
 

Similar threads

  • · Replies 0 ·
Replies
0
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
6K
Replies
3
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
Replies
1
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 19 ·
Replies
19
Views
4K
Replies
1
Views
2K