- #1

tigert2004

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In Figure 33-48a, a light ray in a liquid (n = 1.61) is incident at angle 1 on a boundary with an underlying material, into which some of the light refracts. There are two choices of underlying material. For each, the angle of refraction 2 versus the incident angle 1 is given in Figure 33-48b. Without calculation, note whether the indices of refraction of material 1 and material 2 are greater or less than the index of the liquid.

What is the index of refraction of material 1?

What is the index of refraction of material 2?

I understand that you use snells law,

and

Material #1:

Incident Angle = 67.5 deg

Refraction Angle = 56.25 deg

→ n1 = nwater*Sin(Incid Ang)/Sin(Refr Ang)

= (1.61)*Sin(67.5 deg)/Sin(56.25 deg)

= 1.79

which isn't correct

What is the index of refraction of material 1?

What is the index of refraction of material 2?

I understand that you use snells law,

and

Material #1:

Incident Angle = 67.5 deg

Refraction Angle = 56.25 deg

→ n1 = nwater*Sin(Incid Ang)/Sin(Refr Ang)

= (1.61)*Sin(67.5 deg)/Sin(56.25 deg)

= 1.79

which isn't correct

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