How does the mass on a horizontal spring behave?

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SUMMARY

The discussion focuses on the oscillatory behavior of a 53 gram mass attached to a massless spring, described by the equation y(t) = 1.2*sin(3.1415*t). The spring constant can be calculated using the formula k = mω², where m is the mass in kilograms and ω is the angular frequency. The total mechanical energy, maximum kinetic energy, and maximum velocity of the mass can be derived from the amplitude and angular frequency, leading to specific numerical solutions for each query.

PREREQUISITES
  • Understanding of harmonic motion and oscillation principles
  • Familiarity with spring constant calculations
  • Knowledge of mechanical energy conservation in oscillatory systems
  • Ability to apply trigonometric functions in physical contexts
NEXT STEPS
  • Calculate the spring constant using k = mω² for the given mass and angular frequency
  • Determine the total mechanical energy using E = 0.5*k*A²
  • Find the maximum kinetic energy using KE_max = 0.5*m*v_max²
  • Analyze the maximum velocity using v_max = Aω
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Students and educators in physics, mechanical engineers, and anyone interested in understanding the dynamics of mass-spring systems and harmonic motion.

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A 53 gram mass is attached to a massless spring and allowed to oscillate around an equilibrium according to:
y(t) = 1.2*sin( 3.1415*t ) where y is measured in meters and t in seconds

(a) What is the spring constant in N/m ?

(b) What is the total Mechanical Energy in the mass/spring system?

(c) What is the maximum Kinetic Energy of the mass?

(d) What is the maximum velocity of the mass in m/s ?
 
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