How Does the Plane Wave Equation Define Wavefronts?

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The plane wave equation, expressed as ψ(t) = ψ₀e^{i(⟨k⟩·⟨r⟩ - ωt)}, defines wavefronts through the condition ⟨k⟩·⟨r⟩ = constant, indicating that the phase of the wave is uniform across a plane. This condition implies that at any fixed time, all points on the plane have the same phase, which characterizes a plane wave. The equation also illustrates how wavefronts propagate over time, with the wavefront moving in the direction of the wave vector ⟨k⟩. The propagation velocity of the wave is given by ω/k, where ω is the angular frequency and k is the wave number. Understanding this relationship is crucial for grasping the nature of wave propagation in physics.
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Plane wave equation:

$$\psi(t) = \psi_0e^{i(\vec{k}\cdot\vec{r}-\omega t)}$$

The part that makes the domain of \psi(t_i) a plane is the k dot r part.

I'm reading a book that takes this term and imposes the following condition:

$$\vec{k}\cdot\vec{r}=Const.$$

which, i understand its necessity, but if we just plug in the LHS of the equation, the information on the RHS is lost no? i mean, we didn't use it; we just got rid of it. Can someone clarify this part for me please.
 
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iScience said:
Plane wave equation:

$$\psi(t) = \psi_0e^{i(\vec{k}\cdot\vec{r}-\omega t)}$$

The part that makes the domain of \psi(t_i) a plane is the k dot r part.

I'm reading a book that takes this term and imposes the following condition:

$$\vec{k}\cdot\vec{r}=Const.$$

which, i understand its necessity, but if we just plug in the LHS of the equation, the information on the RHS is lost no? i mean, we didn't use it; we just got rid of it. Can someone clarify this part for me please.

##\vec k\cdot\vec r = \text{const.}## would mean that ##\psi## is a function of time alone.
Isn't a plane wave also a function of space?
http://en.wikipedia.org/wiki/Plane_wave#Arbitrary_direction

You don't "plug in" the LHS of that equation - the equation is a definition of what the LHS means. If you already know what ##\psi(t)## is, then what extra information could the RHS possibly supply?
 
aha! i get it! thanks
 
Hm, I don't get it. What's the book intending to derive/demonstrate? Could you quote more details?
 
iScience said:
Plane wave equation:

$$\psi(t) = \psi_0e^{i(\vec{k}\cdot\vec{r}-\omega t)}$$

The part that makes the domain of \psi(t_i) a plane is the k dot r part.

I'm reading a book that takes this term and imposes the following condition:

$$\vec{k}\cdot\vec{r}=Const.$$

A wave is a traveling disturbance, and the disturbance described by the function ψ depends both on place and time.
$$\vec{k}\cdot\vec{r}=Const.$$ is the equation of a wavefront, a plane, where the phase of the wave is the same at each point. Consider a wavefront where C=0 at t=0, that is, ##\vec{k}\cdot\vec{r}=0## . The equation represents a plane at the origin that is perpendicular to the wave vector ##\vec k##. At a later time t, the points where the phase is zero are on the plane
$$\vec{k}\cdot\vec{r}-ωt=0$$ In case ##\vec k ## is parallel with the x axis, ##\vec k =k\hat e_x##, the plane is perpendicular to the x-axis and its position is determined by ##k x -ωt=0##, that is, at ##x=ω/k t ##: the wavefront travels in the positive x dirction, with speed ω/k. ω/k is the propagation velocity or phase velocity of the wave.

ehild
 
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ehild said:
A wave is a traveling disturbance, and the disturbance described by the function ψ depends both on place and time.
$$\vec{k}\cdot\vec{r}=Const.$$ is the equation of a wavefront, a plane, where the phase of the wave is the same at each point. Consider a wavefront where C=0 at t=0, that is, ##\vec{k}\cdot\vec{r}=0## . The equation represents a plane at the origin that is perpendicular to the wave vector ##\vec k##. At a later time t, the points where the phase is zero are on the plane
$$\vec{k}\cdot\vec{r}-ωt=0$$ In case ##\vec k ## is parallel with the x axis, ##\vec k =k\hat e_x##, the plane is perpendicular to the x-axis and its position is determined by ##k x -ωt=0##, that is, at ##x=ω/k t ##: the wavefront travels in the positive x dirction, with speed ω/k. ω/k is the propagation velocity or phase velocity of the wave.

ehild

What they are saying is NOT that ## \vec{k} \cdot \vec{r} = constant ## everywhere. What they are saying is this: the vector ## \vec{k} ## is a constant, and the vector ## \vec{r} ## can be anything. Now, you pick constant C. Then all the points satisfying the condition ## \vec{k} \cdot \vec{r} = C ## lie on a plane, right? (and not that that plane will be perpendicular to ##\vec{k}##) What we know is that everywhere on that plane the wave function has the same phase at any given instant (fixed t). So all the points on that plane correspond a fixed phase. This is the definition of a plane wave.
 
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