How Does Thermal Energy Compare to Ionization Energy in a Flame?

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SUMMARY

The discussion centers on the comparison between thermal energy and ionization energy in a flame, specifically regarding lithium (Li). The thermal energy is approximated by the equation RT, where R is the gas constant (8.3145 J mol-1 K-1) and T is the temperature in Kelvin. At a flame temperature of 869 ºC, the thermal energy is significantly lower than the first (5.20 x 102 kJ/mol) and second (7.29 x 103 kJ/mol) ionization energies of lithium, indicating that significant ionization of lithium in the flame is not expected. The discussion highlights the importance of understanding energy distributions in thermal contexts.

PREREQUISITES
  • Understanding of Boltzmann distribution in thermodynamics
  • Knowledge of ionization energy concepts
  • Familiarity with the gas constant (R = 8.3145 J mol-1 K-1)
  • Basic principles of flame chemistry and reactivity of elements
NEXT STEPS
  • Explore calculations involving thermal energy and ionization energy comparisons
  • Study the Boltzmann distribution and its applications in chemical thermodynamics
  • Research the reactivity series of elements, focusing on alkali metals
  • Learn about the implications of temperature on ionization processes in flames
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Chemistry students, educators, and professionals interested in thermodynamics, flame chemistry, and the behavior of reactive elements like lithium in high-temperature environments.

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Homework Statement


The energy of particles in a flame at a temperature T might be described by a
Boltzmann distribution. Temperature can be converted to energy (and thereby velocity)
using the gas constant R = 8.3145 J mol-1 K-1. Let us approximate thermal energy in the
flame by RT (squiggly lines mean approximately) where T is in degree Kelvin:
thermal energy ≈ RT
The first ionization energy for Li is 5.20 x 10 2 kJ/mol and the second ionization energy
is 7.29 x 103 kJ/mol. Assume that your Bunsen burner reached 869 ºC, and that nearly all
of Li atoms heated in your Bunsen burner had energies less than 4 x RT. Would you or
would you not expect significant ionization in the flame? Explain.

The Attempt at a Solution


The ionization energy for Li is the opposite of the ionization energy of the flame. The second Li ionization is fairly high, and as a result, I would expect that the ionization energy of the flame is not very significant because the Li ionization is high. Lithium is high on the list of reactive elements, they increase in reactivity going down, example, francium is much more reactive than lithium, I would expect a much larger ionization of flame from franciums ionization compared to lithium.
Am I correct?
 
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physicsnobrain said:
The ionization energy for Li is the opposite of the ionization energy of the flame.
What does "ionization energy of the flame" mean?

physicsnobrain said:
Lithium is high on the list of reactive elements, they increase in reactivity going down, example, francium is much more reactive than lithium, I would expect a much larger ionization of flame from franciums ionization compared to lithium.
I don't understand what this has to do with the problem. You only have to consider lithium in the flame. Is it significantly ionized or not?
 
DrClaude said:
What does "ionization energy of the flame" mean?


I don't understand what this has to do with the problem. You only have to consider lithium in the flame. Is it significantly ionized or not?

no it is not significantly ionized. I said that.
 
physicsnobrain said:
no it is not significantly ionized. I said that.
But based on what? I would like to see some calculations...
 
DrClaude said:
But based on what? I would like to see some calculations...

well obviously R x T is wayyyyyyyyy less than 4(R)(T)

That is why
 
physicsnobrain said:
well obviously R x T is wayyyyyyyyy less than 4(R)(T)
You're comparing ##RT## with ##4RT##? I think you misunderstood the statement of the problem. First, it says that ##E_\mathrm{thermal} \approx RT##, then that ##E_\mathrm{thermal}## is at most ##4RT## (the energy follows a distribution, it is not a fixed value). So how does that compare to the ionization energy?
 

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