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The energy needed to strip all three electrons from a Li(g) atom was found to be 1.96*10^4 kJ/mol. The first ionization energy of Li is 520 kJ/mol. Calculate the second ionization energy of Lithium atoms (the energy required for the process)
Li+(g) ---> Li+2 + e-
Equation: frequency = (3.29x10^15s-1)Z^2(1/n^2i - 1/n^2f)
Ei + hv = Ef
My question: These equations can give me the energy of each energy level but how do I find the energy of required for ionization??
Li+(g) ---> Li+2 + e-
Equation: frequency = (3.29x10^15s-1)Z^2(1/n^2i - 1/n^2f)
Ei + hv = Ef
My question: These equations can give me the energy of each energy level but how do I find the energy of required for ionization??