How Does Vapour Pressure Change at Dew Point for Benzene-Toluene Mixtures?

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cruckshank
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THERE IS NO TEMPLATE BECAUSE GHIS HOMEWORK WAS PLACED IN AN INCORRECT FORUM

Equimolar benzene and and toluene form essentially ideal solutions. At 20degC the vapour of benzene and toluene are 9.866kPa and 2.933kPa respectively. The solution is boiled by reducing the external pressure below the vapour pressure.

What is the vapour pressure when only a few droplets of liquid remain? Assume still at 20degC.

I know I need to use Dalton's/Raoult's Law, but can't work out how to start really. Help would be appreciated, thanks.
 
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