How Does Water Angle in a Rotating Carousel Microwave?

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Homework Help Overview

The problem involves a small container of water placed on a rotating carousel inside a microwave oven, specifically examining the angle of the water surface relative to the horizontal as the carousel rotates. The setup includes parameters such as the radius from the center and the time for one complete revolution.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the forces acting on the water, including pressure differences due to the incline of the surface and the need to equate these to centripetal force. There is also mention of the effects of the container size on the angle of the water surface.

Discussion Status

The discussion is ongoing, with participants sharing their interpretations and attempts to understand the problem. Some have provided insights into the forces involved, while others express confusion regarding the solution and the implications of the rotating frame of reference.

Contextual Notes

There is a note that the container is small, which may influence the assumptions about the angle of the water surface and the pressure distribution within the container.

metallica007
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Homework Statement


A small container of water is placed on a carousel inside a
microwave oven, at a radius of 12.0 cm from the center.
The turntable rotates steadily, turning through one revolu-
tion in each 7.25 s. What angle does the water surface
make with the horizontal?

Homework Equations


F=ma
a=v^2/r
v=(2pi*r)/t

The Attempt at a Solution


The problem is very challenging for me that I did not know how to start think about it!

Note: I attached the solution, could you please explain it to me:approve:
 

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Hey Metallica007,
Frankly, I did not clearly understand their solution and so I will give my attempt at it:

Consider a small volume of water in the container. Let it be a horizontally kept cylinder. Let its area be a and length be l. Since the surface is inclined both the faces of the cylinder would not have equal height of water above them. Hence they have a difference in pressure and hence force on both sides. Equate this difference to the required centripetal force. You will get the value of h/l. This is equal to the tan of the angle.
 
But the angle will change as you go away from the center but not in this case. Because they have given you that the container is small.
 
hi metallica007! :smile:

(have a pi: π and try using the X2 icon just above the Reply box :wink:)

the answer is using a https://www.physicsforums.com/library.php?do=view_item&itemid=87" of reference …

ie, you imagine that you're rotating with the turntable: then Newton's laws all work provided you add a "fictitious" force, the https://www.physicsforums.com/library.php?do=view_item&itemid=84"

so you include that centripetal force on the LHS of Ftotal = 0 :smile:

(if you don't use a rotating frame, you get the same result by putting https://www.physicsforums.com/library.php?do=view_item&itemid=27" on the RHS of Ftotal = ma :wink:)
 
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