The weight of an object varies between the poles and the equator due to the Earth's rotation and its shape. An object with a mass of 80 kg experiences a gravitational acceleration of 9.789 m·s−2 at the equator and 9.832 m·s−2 at the poles. This results in a weight difference, where the centrifugal effect at the equator slightly counteracts gravitational pull, while the poles experience a stronger gravitational force due to the Earth's equatorial bulge and flattened shape. Density variations also contribute to local differences in gravitational acceleration.
PREREQUISITESPhysicists, geophysicists, students studying Earth sciences, and anyone interested in the effects of Earth's rotation on weight and gravity.
That's absolutely correct.georgert said:If I have a mass of 80 kg, what would the difference in my weight be at either the North or South Pole and at the equator? It would seem to me that the spin of the Earth would induce a centrifugal effect that would counter somewhat Earth's gravitational pull at the equator, but not do so at Earth's axis of spin.
local gravity, g, increases from 9.789 m·s−2 at the equator to 9.832 m·s−2 at the poles.[1]