How Far Apart Are Light Fringes in a Double Slit Experiment?

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SUMMARY

The discussion centers on calculating the linear distance between adjacent maxima in a double slit experiment with a wavelength of 740 nm and a slit separation of 0.140 mm, where the screen is positioned 48.0 cm from the slits. The formula used is dy/L = m*wavelength, leading to an incorrect result of 2.5 km for the distance y. The correct interpretation of the calculation reveals that the answer should be significantly smaller, indicating a misunderstanding in the application of the formula or unit conversion.

PREREQUISITES
  • Understanding of wave interference principles
  • Familiarity with the double slit experiment setup
  • Knowledge of unit conversions, particularly between meters and millimeters
  • Proficiency in applying the formula dy/L = m*wavelength
NEXT STEPS
  • Review the derivation and application of the double slit interference formula
  • Practice unit conversion techniques, especially for wavelengths and distances
  • Explore the effects of varying slit separation and wavelength on fringe spacing
  • Investigate the implications of experimental errors in physics calculations
USEFUL FOR

Students studying physics, particularly those focusing on wave mechanics and optics, as well as educators looking to clarify concepts related to the double slit experiment.

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Homework Statement


In a double slit experiment, the wavelength is 740nm, the slit separation is 0.140mm, and the screen is 48.0cm away from the slits. What is the linear distance between adjacent maxima on the screen? Please check my answer.


Homework Equations


dy/L = m*wavelength


The Attempt at a Solution


y = [1(740x10^-9 m)(0.48m)]/(0.140x10^-3m)
y = 2.5 x 10^3 m

Thanks!
 
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hardwork said:
y = 2.5 x 10^3 m

2.5 kilometers is much too large an answer here.
 

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