The discussion revolves around determining the maximum number of bright fringes that can be formed in a double slit experiment using light of a specific wavelength and slit separation. The problem is situated within the context of wave optics.
The discussion is ongoing, with participants exploring different interpretations of the fringe calculation and questioning the assumptions made regarding the rounding of results. Some guidance has been offered regarding the implications of the calculated fringe number.
There is a noted lack of information about the width of the slits, which some participants suggest is critical for fully addressing the problem. Additionally, there is uncertainty about the physical feasibility of the sixth fringe based on the calculated value.
Can the 6th fringe form?Starrrrr said:Homework Statement
At most, how many bright fringes can be formed on either side of the central bright fringe when light of wavelength 644 nm falls on a double slit whose slit separation is 3.64 × 10-6 m?
Homework Equations
m=dsintheta/lamdbaThe Attempt at a Solution
m=(3.64x10e-6)(1)/644x10e-9) = 5.65 which is 6 bright fringes right but the system telling me it's wrong?[/B]
I'm not sure so I'm guessing noehild said:Can the 6th fringe form?
Last time I checked, 5.65<6.Starrrrr said:5.65 which is 6 bright fringes
What would be sin(θ) at the 6th fringe? Is it possible?Starrrrr said:I'm not sure so I'm guessing no